10 1/3 = 10 3/9
3/9 + 7/9 = 1
10 + 1 = 11
Answer = 11
The strategy for winning every time appears to be to ensure that the remaining number of coins is a multiple of 6. Then the first player can ensure a win by taking 2 coins to make the total number be 48.
The range is {y E R: y < or = 0}
Answer:
I think The answer is ( -10, 10 )
