X = smaller number, y = larger number
x + y = 15.....x = 15 - y
4x = 2y - 60
4(15 - y) = 2y - 60
60 - 4y = 2y - 60
60 + 60 = 2y + 4y
120 = 6y
120/6 = y
20 = y <==== larger number is 20
x + y = 15
x + 20 = 15
x = 15 - 20
x = - 5
Slope:
2
3
y-intercept: (0,−6)xy0−63−4
Answer:
D. 15P15 * 10P5
Step-by-step explanation:
Since you have to place all first-grade students in the first three rows, and nowhere else, we have to make a special calculation for that, then another for the rest of the bus.
These are permutations since the order is important. If we sit John, Paul, Ringo, George and Pete in this order in the first row it's a different way than seating them (in the same order) in the second row for example.
For the 15 first-graders of the first three rows (15 seats), we have 15P15 since all 15 places have to be occupied by all 15 first-graders.
Then we have 10 remaining seats left to be assigned to the 5 second-graders. That is 10P5.
We then multiply the permutation numbers of those two arrangements to get the total ways:
15P15 * 10P5, answer D.
She should check her actual quotient again, carefully. Something is
definitely wrong. The spread between her estimate and the actual
quotient is too much. She probably made a mistake with (at least)
one of them.
Since the estimate was just for her own convenience and the actual
quotient was the one that really counts, she should go straight to the
actual quotient and look there for a mistake first.
Im pretty sure the answer is false
