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ikadub [295]
3 years ago
11

12 pts? Harris and Annabelle are 200 feet apart, and they are standing on opposite sides of a tree. The angles of elevation from

Harris to the top of the tree is 30°, and the angle of elevation from Annabelle to the top of the tree is 35°. Find the height of the tree. Round your answer to the nearest tenth.
Mathematics
1 answer:
Sergio [31]3 years ago
5 0
If we are to connect the root of the tree to a person to the top of the tree, we form two right triangles. If we let x and and 200 - x be the distance of Harris and Annabelle from the tree, respectively and h be the height, we form the trigonometric functions,
                                       tan 30° = h/x
                                       tan 35° = h/(200 - x)
The values of h and x in the equations are 63.28 ft and 109.62 ft, respectively. Thus, the answer to this item is approximately 63.28 ft. 
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What is the real part of the complex number -3+9i
VikaD [51]

The real part of given complex number -3 + 9i is -3

<em><u>Solution:</u></em>

We have to find the real part of complex number -3 + 9i

A Complex Number is a combination of real Number and an imaginary Number

<em><u>The general form of complex number is:</u></em>

a + bi

Where "a" and "b" are real numbers and i is the unit imaginary number

The given complex number is:

-3 + 9i

On comparing the above complex number with general form of complex number we get,

Real part = -3

Thus real part of given complex number is -3

8 0
3 years ago
What is 55x+6=120<br><br> (Fraction form)
mezya [45]

Step-by-step explanation:

55x+6=120

55x=120-6

55x=114

X=114/55

8 0
3 years ago
In a football game, a team loses 8 yards, then loses 3 yards, then loses 11 yards.
stich3 [128]

Answer:

the lost 22 yards altogether

they now have -22 yards i believe

8 0
3 years ago
Read 2 more answers
The line that contains the point Q( 1, -2) and is parallel to the line whose equation is
Triss [41]
Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.

If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

y-4=\frac { 2 }{ 3 } \left( x-3 \right) \\ \\ y-4=\frac { 2 }{ 3 } x-2\\ \\ y=\frac { 2 }{ 3 } x-2+4\\ \\ y=\frac { 2 }{ 3 } x+2

So, at the moment, our parallel line looks like this...

y=(2/3)*x + C

However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.

-2=(2/3)*(1) + C

Therefore:

C = - 2 - (2/3)

C = - 6/3 - 2/3

C = - 8/3

This means that the line you are looking for is:

y=(2/3)*x - (8/3)

Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.

3 0
3 years ago
14. Two parallel lines l and m are intersected by a transversal t. If the interior angles on same side of transversal are (2x−8)
nlexa [21]

Answer:

70° and 110°

Step-by-step explanation:

It is given that, two parallel lines l and m are intersected by a transversal t.

The interior angles on same side of transversal are (2x−8)° and (3x−7)°.

We need to find the measure of these angles.

We know that, the sum of interior angles of the same side of the  transversal is equal to 180°. So,

(2x−8)° + (3x−7)° = 180°

⇒ 5x-15=180°

⇒5x=180°+15

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⇒x=39

Put x = 39 in (2x−8)°,

(2x−8)° = (2(39)-8)°

=70°

Again put x = 39 in (3x−7)°,

(3x−7)° = (3(39)-7)°

=110°

So, the measure of these angles are 70° and 110°.

8 0
3 years ago
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