The real part of given complex number -3 + 9i is -3
<em><u>Solution:</u></em>
We have to find the real part of complex number -3 + 9i
A Complex Number is a combination of real Number and an imaginary Number
<em><u>The general form of complex number is:</u></em>
a + bi
Where "a" and "b" are real numbers and i is the unit imaginary number
The given complex number is:
-3 + 9i
On comparing the above complex number with general form of complex number we get,
Real part = -3
Thus real part of given complex number is -3
Step-by-step explanation:
55x+6=120
55x=120-6
55x=114
X=114/55
Answer:
the lost 22 yards altogether
they now have -22 yards i believe
Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.
If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

So, at the moment, our parallel line looks like this...
y=(2/3)*x + C
However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.
-2=(2/3)*(1) + C
Therefore:
C = - 2 - (2/3)
C = - 6/3 - 2/3
C = - 8/3
This means that the line you are looking for is:
y=(2/3)*x - (8/3)
Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.
Answer:
70° and 110°
Step-by-step explanation:
It is given that, two parallel lines l and m are intersected by a transversal t.
The interior angles on same side of transversal are (2x−8)° and (3x−7)°.
We need to find the measure of these angles.
We know that, the sum of interior angles of the same side of the transversal is equal to 180°. So,
(2x−8)° + (3x−7)° = 180°
⇒ 5x-15=180°
⇒5x=180°+15
⇒5x=195
⇒x=39
Put x = 39 in (2x−8)°,
(2x−8)° = (2(39)-8)°
=70°
Again put x = 39 in (3x−7)°,
(3x−7)° = (3(39)-7)°
=110°
So, the measure of these angles are 70° and 110°.