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3 years ago

Select the sets that are not functions.

Mathematics

1 answer:

Kaylis [27]3 years ago

7 0

Answer:

D,E are not functions

Step-by-step explanation:

A function is a relation in which every input has not more than one output.But the output of the inputs may be same.Here in D the input 1 has 4 different outputs as 1,2,3,4.So its not a function.Similarly in E 6 has 2 outputs as 2 and -1.For remaining sets the inputs has only one output.so they are functions.

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0.5(x^4-7)+16 what is the answer your answer should contain decimals.

svlad2 [7]

The answer should be 0.5x^4+12.5

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3 years ago

Suppose that 20% of students at high school A and 18% of students at high school B participate on a school athletic team. Indepe

daser333 [38]

Answer:

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Step-by-step explanation:

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3 years ago

Someone please help me

Firdavs [7]

Answer:

x = -3/2

Step-by-step explanation:

The removable discontinuity is at the value of x where a denominator factor cancels a numerator factor, and those factors are zero.

$p(x)=\dfrac{2x+3}{4x^2-9}=\dfrac{2x+3}{(2x+3)(2x-3)}=\dfrac{2x+3}{2x+3}\cdot\dfrac{1}{2x-3}\\\\p(x)=\dfrac{1}{2x-3}\qquad x\ne-3/2$

That cancellation occurs where 2x+3 = 0, at x=-3/2.

The function p(x) has a removable discontinuity when x = -3/2.

4 0

3 years ago

A line passes through the point (-8, 7) and has a slope of negative 3/4Write an equation in slope-intercept form for this line.

Arlecino [84]

Answer:

$y=-\frac{3}{4}x+1$

Step-by-step explanation:

We do not have enough information for slope intercept form. But we can use the point-slope formula to find the information. The formula is $y -y_{1} =m(x -x_{1})$ where we substitute a point (x,y) for $(x_{1},y_{1})$ .

We have m=-3/4 and (-8, 7). We input m and $x_{1} =-8\\y_{1}=7$ .

$y-7=-\frac{3}{4} (x-(-8))\\y-7=-\frac{3}{4} (x+8)$

We now simplify the parenthesis and solve for y.

$y-7=-\frac{3}{4} (x+8)\\y-7=-\frac{3}{4}x+-\frac{3}{4} (8)$

We convert 8 into a fraction with 1 as the denoinator.

$y-7=-\frac{3}{4}x+-\frac{3}{4} (\frac{8}{1} )\\y-7=-\frac{3}{4}x+-\frac{24}{4}\\y-7=-\frac{3}{4}x+-6$

We add 7 to both sides to isolate y,

$y-7+7=-\frac{3}{4}x+-6+7\\y=-\frac{3}{4}x+1$

This is slope intercept form. The line as slope -3/4 and y-intercept (0,1) or b=1.

5 0

3 years ago

Hey can anyone help me with this

hichkok12 [17]

Answer:

$5\sqrt{3}$ , or 8.7

Step-by-step explanation:

To solve this problem, you need to use the Pythagorean theorem $a^{2} +b^{2} =c^{2}$ . The tricky part is visualizing where the right triangle will be in the cube. The diagonal you are trying to find will be the hypotenuse, the diagonal of the base of the cube is one leg, and the edge of the cube is another leg.

First, you need to find the lengths of both legs of the triangle. The first leg is the length of the edge of the cube, which is given as 5 cm.

The next leg is the diagonal of the base of the cube, which is a 5x5 square. To find the diagonal of the 5x5 square, you can cut the square across its diagonal and use the 45-45-90 special right triangle rule. Each leg of the newly formed 45-45-90 triangle is 5 cm, which can be represented by x, and the hypotenuse, which is also the diagonal of the original 5x5 square, can be represented as $x\sqrt{2}$ .

Using 5 as x and substituting, you can find that the diagonal of the 5x5 square is $5\sqrt{2}$ cm, so the second leg of the right triangle is $5\sqrt{2}$ cm.

Now, you can do a final substitution of both legs into the Pythagorean theorem, which turns out as $(5\sqrt{2})^{2} +5^{2} =c^{2}$

Solving this equation starts with doing out the squares on the left side as $50+25=c^{2}$ which means $c^{2} =75$ . From here you take the square root of both sides of the equation to get $c=\sqrt{75}$ or $c=5\sqrt{3}$ .

The final step is to make this solution rational by rounding it, so plug in $5\sqrt{3}$ into a calculator and round to the nearest tenth to get 8.7.

6 0

3 years ago