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2 years ago

Geometry. Very basic.

Mathematics

1 answer:

AveGali [126]2 years ago

6 0

Answer:

A)10.25 cm ; B)5 square cm

Step-by-step explanation:

Formula:

p=(a+b+c) [p= perimeter ; a,b , and c are the side lengths.]

∴The perimeter of the triangle =(4+2.75+3.5) cm

=10.25 cm

Formula:

A = 1/2 . b .h [A=area ; b= base ; h= height]

∴The area of the triangle = (1/2 . 4 . 2.5) square cm [b=4 ; h=2.5]

=5 square cm

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Please I need some answers

Ilia_Sergeevich [38]

-6 x -4 = 24
24/-6 = -4
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Hope this helps :)

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2 years ago

2x^2=9-3x <br> Find the factors

d1i1m1o1n [39]

Answer:

x = -3, $\frac{3}{2}$

Step-by-step explanation:

The given quadratic equation is: $2x^2 = 9 - 3x$

This can be written as: $2x^2 + 3x - 9 = 0$

To solve a quadratic equation of the form $ax^2 + bx + c = 0$ we use the formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)}$

$\implies x = \frac{-3 \pm \sqrt{81}}{4}$

$\implies x = \frac{-3 \pm 9}{4}$

We get two values of 'x', viz.,

x = $\frac{-3 + 9}{4}$ and $\frac{- 3 - 9}{4}$

$\implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4}$

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $\frac{3}{2}$ ) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $\frac{3}{2}$ to see that this indeed is the given quadratic equation.

5 0

3 years ago

T÷5/12= -3/10<br> Thank you if you help :)

skelet666 [1.2K]

Answer:

t = -1/8.

Step-by-step explanation:

t / 5/12 = -3/10 Invert the 5/12 and multiply:

12t / 5 = -3/10

Cross multiply:

12t * 10 = 5 * -3

120t = -15

t = -15/120 = -1/8.

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2 years ago

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NeTakaya

Answer: 5

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3 years ago

Find the area simply your answer

Goshia [24]

Area=base*height

A=(x+6)(2x+2)

A=2(x+1)(x+6) technically this is the simplified form, but they may want the expanded form...

A=2x^2+14x+12

3 0

3 years ago