Answer:
where 
Step-by-step explanation:
Recursive means you want to define a sequence in terms of other terms of your sequence.
The common ratio is what term divided by previous term equals.
The common ratio here is -6/2=18/-6=-54/18=-3.
Or in terms of the nth and previous term we could say:
where r is -3
Multiply both sides by the a_(n-1).
where
Yes, you are right. To solve for a variable means to put it on one side by itself, in terms of the other variables or values. To move something to the opposite side you do the opposite operation. Then you do the same thing to both sides of the equation.
Answer:
The amount $ 8114.3 is the balance in the account after eleven years
Step-by-step explanation:
From;
A= P(1+r)^n
Where;
A= amount
P= principal
r= interest rate
n= time
A= 5000(1+ 0.045)^11
A= 5000(1.045)^11
A= $ 8114.3
The amount $ 8114.3 is the balance in the account after eleven years.
Answer:
Exponential decay.
Step-by-step explanation:
You can use a graphing utility to check this pretty quickly, but you can also look at the equation and get the answer. Since the function has a variable in the exponent, it definitely won't be a linear equation. Quadratic equations are ones of the form ax^2 + bx + c, and your function doesn't look like that, so already you've ruled out two answers.
From the start, since we have a variable in the exponent, we can recognize that it's exponential. Figuring out growth or decay is a little more complicated. Having a negative sign out front can flip the graph; having a negative sign in the exponent flips the graph, too. In your case, you have no negatives; just 2(1/2)^x. What you need to note here, and you could use a few test points to check, is that as x gets bigger, (1/2) will get smaller and smaller. Think about it. When x = 0, 2(1/2)^0 simplifies to just 2. When x = 1, 2(1/2)^1 simplifies to 1. Already, we can tell that this graph is declining, but if you want to make sure, try a really big value for x, like 100. 2(1/2)^100 is a value very very very veeery close to 0. Therefore, you can tell that as the exponent gets larger, the value of the function goes down and gets closer and closer to zero. This means that it can't be exponential growth. In the case of exponential growth, as the exponent gets bigger, your output should increase, too.
