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Lena [83]
3 years ago
15

I need help figuring out which two grids have the same % please

Mathematics
2 answers:
Bumek [7]3 years ago
7 0

Answer:

a and c

Step-by-step explanation:

A has 3 out of a total of 6 shaded, and that would be 3/6. 3/6 simplifies into 1/2 which is also 50%. Same with c. 2 out of four pieces are shaded, 2/4. 2/4 becomes 1/2 which is also 50%.

tigry1 [53]3 years ago
3 0

Answer:

a and c

Step-by-step explanation:

The first one is 3/6 = 50%

The second one is 3/8 = 37.5%

The third one is 2/4 = 50%

The fourth one is 5/8 = 62.5%

The ones with the same percent shaded are the first and third

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The percent of people of smoke cigarettes is 20.9%..
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help please!! find the area of each triangle. round intermediate values to the nearest tenth. use the rounded values to calculat
White raven [17]

Area of a triangle = (1/2)*base*height

For both of the triangles, you have the base (8.8 for the triangle on the left, 7.6 for the triangle on the right) and the side lengths, but not the height. But since both are isosceles triangles, you can find the height using the pythagorean theorem.

5.

First divide the triangle vertically into two triangles (see attached picture). Now you have two right triangles, you can apply the pythagorean theorem on either one of them to find the height. The pythagorean theorem says that for a right triangle, a^2+b^2=c^2, where c is the hypotenuse and a and b are the sides of the triangle.

Substituting the given values and rounding to nearest tenth:

a^2+b^2=c^2\\4.4^2+h^2=10^2\\h=9.0

Now that you have the height, you can find the area of the entire triangle.

A = (1/2)*base*height

A = (1/2)*8.8*9.0 = 39.6

6.

Same procedure.

a^2+b^2=c^2\\3.8^2+h^2=10^2\\h=9.2

A = (1/2)*base*height

A = (1/2)*7.6*9.2 = 35.0

7 0
3 years ago
The cooper family owns a luxury sedan and a compact car. The fuel tank capacity of the luxury sedan 9s 22.45 gallons and that of
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Answer:

13.75\ gal

Step-by-step explanation:

we know that

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4 0
4 years ago
Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:
kondaur [170]
\text{Proof by induction:}
\text{Test that the statement holds or n = 1}

LHS = (3 - 2)^{2} = 1
RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS
\text{Thus, the statement holds for the base case.}

\text{Assume the statement holds for some arbitrary term, n= k}
1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}

\text{Prove it is true for n = k + 1}
RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}

LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}
= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}
= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}
= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}
= \frac{k(6k^{2} + 15k + 11) + 2}{}
= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}
= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}
= RHS

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.
3 0
3 years ago
Please help<br> x2 + 14x + 37 = 0
tatiyna

Answer:

x = −37/16

This is the value of x which completes the equation properly, unless you mean x^2 instead of x2.

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