Answer:
h'(x) = 0.6 and Δx = 1 and 2
h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6
h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2
Explanation below:
Step-by-step explanation:
Based on the information given we have that when the climber is 6000 meters from the start, his elevation is 8000 meters above sea level.
We know that the function for elevation is given by h(x) where x is the number of meters from the start.
Therefore, h(6000) = 8000.
We also know that the derivative of a function tells us the reason of change at some point (or how fast a function is changing near that point). For this problem we have that h'(x) = 0.6. (<u>meaning that the elevation increases in 0.6 meters for every meter they hike further nearby the 6000 meters</u>)
We need to use the derivative at a point to estimate values of the function at nearby points
We're going to use h'(x)= 0.6. Δx= 1
h(6001) = h(6000) + h'(6000)(1) = 8000 +0.6 = 8,000.6
Therefore h (6001) = 8,000.6
Now for h'(x)= 0.6. Δx= 1
h(6002) = h(6000) + h'(6000)(2) = 8000 + 0.6 (2) =8000 +1.2 = 8001.2
Therefore h(6002) = 8001.2
