Find the cross product (7,-4,5) x (6,2,9). is the resulting vector perpendicular to the given vectors ?

How to find the perimeter of a right triangle

QveST [7]

Answer:

There are three primary methods used to find the perimeter of a right triangle.

1. When side lengths are given, add them together.

2. Solve for a missing side using the Pythagorean theorem.

3. If we know side-angle-side information, solve for the missing side using the Law of Cosines.

Step-by-step explanation:

there i hope this helps!!!

6 0

3 years ago

Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.

Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

$\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0$

$\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill$

3 0

3 years ago

13.) Solve for M<br> 14.) Solve for A<br> 17.) Solve for H

brilliants [131]

Answer:

See Below (Isolate the variables)

Step-by-step explanation:

13) d = 4AM solve for M

Divide both sides by 4A

$\frac{d= 4AM}{4A}$

$\frac{d}{4A} = M$

14) $\frac{A}{6}$ = f+h solve for A

Multiply both sides by 6

A = 6( f+h)

15) h - m = qb solve for H

Add m to both sides

h - m = qb

+ m +m

h = qb + m

3 0

3 years ago

How would you describe a meter in English units?

dalvyx [7]

The answer is letter A. A meter has nearly the same value to a yard, one yard approximately amounting to 1.09361 meter. The rest of the other measures are far from meter's value in distance.

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

5 0

3 years ago

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Expand quadratic equation (2x-3)(x+4) = 0

OleMash [197]

Answer:

Step-by-step explanation:

Simplifying

(2x + -3)(x + -4) = 0

Reorder the terms:

(-3 + 2x)(x + -4) = 0

Reorder the terms:

(-3 + 2x)(-4 + x) = 0

Multiply (-3 + 2x) * (-4 + x)

(-3(-4 + x) + 2x * (-4 + x)) = 0

((-4 * -3 + x * -3) + 2x * (-4 + x)) = 0

((12 + -3x) + 2x * (-4 + x)) = 0

(12 + -3x + (-4 * 2x + x * 2x)) = 0

(12 + -3x + (-8x + 2x2)) = 0

Combine like terms: -3x + -8x = -11x

(12 + -11x + 2x2) = 0

Solving

12 + -11x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.

(3 + -2x)(4 + -1x) = 0

Subproblem 1

Set the factor '(3 + -2x)' equal to zero and attempt to solve:

Simplifying

3 + -2x = 0

Solving

3 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.

3 + -3 + -2x = 0 + -3

Combine like terms: 3 + -3 = 0

0 + -2x = 0 + -3

-2x = 0 + -3

Combine like terms: 0 + -3 = -3

-2x = -3

Divide each side by '-2'.

x = 1.5

Simplifying

x = 1.5

Subproblem 2

Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying

4 + -1x = 0

Solving

4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0

0 + -1x = 0 + -4

-1x = 0 + -4

Combine like terms: 0 + -4 = -4

-1x = -4

Divide each side by '-1'.

x = 4

Simplifying

x = 4

Solution

x = {1.5, 4}

6 0

2 years ago

Read 2 more answers