Question

A rectangular dartboard has an area of 648 square centimeters. The triangular part of the dartboard has an area of 162 square centimeters. A dart is randomly thrown at the dartboard. Assuming the dart lands in the rectangle, what is the probability that it lands inside the triangle? To the nearest whole percent, the probability is

Answer 1

162 divide by 648 is equal to 1/4, or 25%

Answer 2

Answer: 25%

Step-by-step explanation:

Given : A rectangular dartboard has an area of 648 square centimeters.

The triangular part of the dartboard has an area of 162 square centimeters.

If we assume that the dart lands in the rectangle, then the probability that it lands inside the triangle will be :-

$\dfrac{\text{Area of triangular part}}{\text{Area of rectangular dart board}}\\\\=\dfrac{162}{648}=0.25$

In percent, $0.25\times100=25\%$

Hence, the required probability = 25%