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Cerrena [4.2K]
3 years ago
9

Admission to the fair costs $5. Each ticket for a ride costs $1.50. You have $20 to spend at the fair on admissions and rides. E

xpress the number of tickets you can buy as an inequality.
Mathematics
1 answer:
nikklg [1K]3 years ago
3 0
You can but over 40 that’s would be the number
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Please help fasttt!!
gogolik [260]

Answer:

then u help me

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If p(x)=x^3-3x^2-x+3 and p(3)=0, what is a factor of p(x)
IRISSAK [1]
<h3>Answer:   x-3</h3>

Since p(3) = 0, this means x = 3 plugs into p(x) to get 0

We can write p(x) as p(x) = (x-3)q(x) where q(x) is some other polynomial that multiplies with (x-3) to lead to x^3-3x^2-x+3

Let's plug in x = 3 and see what happens

p(x) = (x-3)q(x)

p(3) = (3-3)q(3)

p(3) = 0*q(3)

p(3) = 0

No matter what the result of q(3) was, it doesn't matter because it multiplies with 0 to get 0.

The general rule is: if p(k) = 0, then x-k is a factor of p(x). This is a special case of the remainder theorem.

8 0
3 years ago
If it is 5º outside and the temperature will drop 17° in the next six hours,
attashe74 [19]
It will be -15 outside, it’s gonna get cold
6 0
3 years ago
Read 2 more answers
A medical insurance company offers two​ prescription-drug insurance plans. With plan​ 1, James would pay the first ​$150 of his
vodka [1.7K]

Answer:

when expenses are greater than $433.33

Step-by-step explanation:

set up equations for each plan

let 'x' = prescription costs

Plan 1:  y = 150 + .5x

Plan 2:  y = 280 + .2x

150 + .5x = 280 + .2x

.5x = 130 + .2x

.3x = 130

x = 433.33

i checked my answer by graphing each equation and $433.33 is the break-even point where each plan would have the same costs but, after that, the expenses for Plan B are less

6 0
3 years ago
What is the solution to this inequality?
Mumz [18]

Answer:

x> 1

Step-by-step explanation:

X-7>-6

Add 7 to each side

X-7+7>-6+7

x> 1

3 0
3 years ago
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