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VikaD [51]
3 years ago
12

156872/3756 quotient remainder

Mathematics
1 answer:
andreev551 [17]3 years ago
3 0
41.8 rounded to the nearest tenth

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How can this be solved?
Ad libitum [116K]

Answer:

by multiplying all numbers seperatly by each other and adding those

Step-by-step explanation:

7 0
3 years ago
Which of this fraction are greater then1/2 but less then 3/4 .7/8 .2/5 .1/3 .5/8 .3/6
avanturin [10]

Answer: 7/8


Step-by-step explanation:

think of each faction as a pie or pizza.

each one will have the number of slices as the bottom number of the fraction.

now shade in the top numbers and see if it more than your 1/2

you will see 7/8 is the answer since it will be one piece left from being complete or "gone"

hope this helped angel!!


4 0
3 years ago
Solve the equation for y<br> Y minus 5 equals 1/3 (x plus 12)
Vinvika [58]

Answer:

ok so this problem you are basically just rearranging it. you're going to want y by itself.

Step-by-step explanation:

let's start with the original equation: 5-y=1/3x +12

so first you have to move the five over, so you subtract 5 from both sides. -y=1/3x+12-5

then you subtract the 5 from the twelve since they're like terms: -y=1/3x+7

and finally you have to move the negative over. when you move the negative think of it like dividing negative one from both sides, everything on the other side has to get the negative.

so we're left with y=-1/3x-7

I hope this helps!

5 0
3 years ago
In a bag of 50 marbles, 20 marbles are blue or pink.
Scorpion4ik [409]

Answer:

40%

Step-by-step explanation:

The ratio is 20:50, we can expand to 40:100, so 40%

8 0
3 years ago
Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
2 years ago
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