156872/3756 quotient remainder

Four polynomials are shown below:

nikklg [1K]

Both B and D are 3rd degree, but only D is a 3rd degree binomial because it has only 2 terms. The answer is D.

3 0

3 years ago

How are the divisibility rules involved with the simplification of fractions?

Rashid [163]

Because when you simplify a fraction you divide the number on bottom be the top number to simplify the fraction and make it a mixed number

5 0

3 years ago

Ayuda plis es para hoy

aivan3 [116]

Es la segunda media es 1.65, mediana es 1.65, y modo es 1.61

5 0

3 years ago

Shamir and Juliet are traveling at constant rates in their cars. If Shamir travels

snow_lady [41]

How much farther than Shamir will Juliet travel in one hour is : b. 3 miles.

<h3>Distance</h3>

1 hour= 60 minutes

Given:

Difference in 10 minutes=1/2 mile

Hence:

Difference in one hour=1/2×(60/10)

Difference in one hour=1/2× 6 mile

Difference in one hour=3 miles

Therefore how much farther than Shamir will Juliet travel in one hour is : b. 3 miles.

Learn more about distance here:brainly.com/question/2854969

#SPJ1

5 0

2 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

(C) Tan(A + B) = $\frac{Sin(A +B)}{Cos(A + B)}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

3 years ago