Question

Use algebraic means to show that x^2 + y^2 = 8 is not a function. Explain your process.

Answer 1

Answer:

For a single value of x function has more than one corresponding value of y which satisfies the equation.

Step-by-step explanation:

Function: A relationship between a set of inputs and a set of possible outputs, where exactly one output is associated with each input.

It means for an equation to represent a function any single value of  x there should be only one corresponding value of  y which satisfies the equation.

Now consider the given equation.

$x^2 + y^2 = 8$

If we put x=0 then we get two value of y i.e $\sqrt8$ and $-\sqrt8$ which satisfy the equation  and therefore the equation is not a function.