The we should use ANOVA instead of several t-tests to evaluate the differences in the mean of three or more groups.
<h3>What is t test?</h3>
A t- test is a measurable test that is utilized to look at the method for two gatherings. It is many times utilized in speculation testing to decide if a cycle or treatment really meaningfully affects the number of inhabitants in interest, or whether two gatherings are not quite the same as each other.
<h3>Explain ANOVA test:</h3>
The ANOVA test permits an examination of multiple gatherings simultaneously to decide if a relationship exists between them.
<h3 /><h3>According to question:</h3>
We ought to utilize ANOVA rather than a few t-tests to assess the distinctions in the mean of at least three gatherings on the grounds that without fail, we direct a t-test (between two gatherings) there is some opportunity that a Kind I blunder is being made while doing the test.
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Answer: Choice D
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Explanation:
It might help to turn the image sideways so that it is rotated 90 degrees. Have the triangle facing upward with (x1,y2) and (x1,y1) as the base points. The base has a length of (y2-y1) as this is the difference of y coordinate values. The x coordinate being the same indicates we simply subtract.
The height is (x3-x1) which is the difference of the x coordinates for either left point and the right point
So,
area = (1/2)*base*height
area = (1/2)*(y2-y1)*(x3-x1)
which is why choice D is the answer
So we want to solve like if it was just a basic equation. We start with 25+3.50x<17+7.50x and get rid of our smallest x. That means we get rid of the 3.50x by subtracting from both sides and our new equation is 25<17+4x. Let’s get our x by itself shall we, so let’s subtract 17 from both sides and we get 8<4x. Finally all we do is divide by 4 and just like that 2
Answer:
it's option D.
Step-by-step explanation:
see attachment in case u need steps
Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:
Hence the bounds of the interval are found as follows:
The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
