Answer:
The correct option is (A).
Step-by-step explanation:
The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:
![EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)](https://tex.z-dn.net/?f=EER%20%3D%20662%20-%20%289.53%20%5Ctimes%20AGE%29%20%2B%20PA%20%5Ctimes%20%2815.91%20%5Ctimes%20WT%20%2B%20539%20%5Ctimes%20HT%29)
Here,
AGE = age counted in years
PA = appropriate physical activity factor
WT = weight in kilograms
HT = height in meters
The physical activity factor for men and women is:
Activity Level PA (men) PA (Women)
Sedentary 1.00 1.00
Low 1.11 1.12
Active 1.25 1.27
Very Active 1.48 1.45
Given:
AGE = 22 year-old male college student
PA = low = 1.11
WT = 180 pounds = 81.6466 kg
HT = 5'10" = 1.778 m
Compute the value of EER as follows:
![EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)](https://tex.z-dn.net/?f=EER%20%3D%20662%20-%20%289.53%20%5Ctimes%20AGE%29%20%2B%20PA%20%5Ctimes%20%2815.91%20%5Ctimes%20WT%20%2B%20539%20%5Ctimes%20HT%29)
![= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962](https://tex.z-dn.net/?f=%3D%20662%20-%20%289.53%20%5Ctimes%2022%29%20%2B%201.11%20%5Ctimes%20%2815.91%20%5Ctimes%2081.6466%20%2B%20539%20%5Ctimes%201.778%29%5C%5C%5C%5C%3D662-209.66%2B1.11%5Ctimes%20%281298.997406%2B958.342%29%5C%5C%5C%5C%3D452.34%2B2505.64674066%5C%5C%5C%5C%3D2957.98674066%5C%5C%5C%5C%5Capprox%202962)
Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.
The correct option is (A).
Answer:
a) y = -5 b) y = -4 c) y = 4 d) y = 11
Step-by-step explanation:
a) (-2+2)²-5
b) (-1+2)²-5
c) (1+2)²-5
d) (2+2)²-5
Equation to find number's value: ![\frac{1}{5}n + 3n = 2n + 42](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7Dn%20%2B%203n%20%3D%202n%20%2B%2042)
Number's value: n = 35
Explanation:
Let n be the unknown number for this problem.
One fifth of a number is the same as
.
Three times the number is the same as 3n.
Twice the number plus 42 is the same as 2n + 42.
So, using the information we've gathered so far, we can create the equation that will provide us with n's value.
Equation: ![\frac{1}{5}n + 3n = 2n + 42](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7Dn%20%2B%203n%20%3D%202n%20%2B%2042)
We can use this equation to find n's value.
You can subtract 2n from both sides to get the equation
, which is the same thing as the equation we were using.
Now add n and
together to get
.
After you do this, your equation should look like
.
Now divide both sides by
to get n's value.
n = 35