Simplify: 3(n-2) whats the answer?

Mathematics

1 answer:

Pie3 years ago

3 0

Answer: 3n-6

Step-by-step explanation: You have to use the distributive property. 3 times n is 3n and 3 times -2 is -6.

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A ladder 10 ft long rests against a vertical wall. Let theta be the angle between the top of the ladder and the wall and let be

IgorC [24]

Answer:

5 ft/s

Step-by-step explanation:

Let L be the length of the ladder. The relation between the angle and distance X is:

X = L * sin θ the change of X will be:

dX/dt = L * cos θ If we evaluate the expression when θ = π/3, we get the change of X:

dX/dt = 10 * cos(π/3)

dX/dt = 5 ft/s

4 0

3 years ago

Please help me solve this?

jenyasd209 [6]

Recipe is for 24 pieces, and required quantity is 16.

So the ratio is 16/24 = 2/3 means we need to reduce all ingredients to 2/3 of the given quantities. Not all recipes can be reduced prorata, but we will assume it can be done. A word of caution: the measurement of quantities will become awkward (like 3/8 of a teaspoon of salt, etc). The practical way is to make the full recipe, and invite friends to take home the remainder.

Here's the scaled recipe

Butter 1cup*3/4 = 3/4 cup

unsweetened chocolate = 4*3/4 = 3 squares

white sugar = 2 * 3/4 = 1 1/2 cups

eggs = 4 * 3/4 = 3 eggs

A.P. flour = 1 cup * 3/4 = 3/4 cups

vanilla extract = 1 * 3/4 = 3/4 teaspoons

salt = 1/2 * 3/4 = 3/8 teaspoons

chopped walnuts = 2 * 3/4 = 1 1/2 cups

For this reason, there is a trend to use weights (in grams) than volumes to make scaling recipes easier.

6 0

3 years ago

a plane flies 5.0km due north from a point O and then 6.0km on a bearing of 060° the pilot then changes course on a bearing of 1

Virty [35]

The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

A plane that travels a distance $r$ , in kilometers, with a bearing of $\theta$ sexagesimal degrees can be represented in standard position by means of the following expression:

$\vec r = r\cdot (\sin\theta, \cos \theta)$ (1)

We can obtain the resulting vector ( $\vec R$ ) by the principle of superposition:

$\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})]$ (2)

If we know that $r_{1} = 5\,km$ , $\theta_{1} = 0^{\circ}$ , $r_{2} = 6\,km$ , $\theta_{2} = 60^{\circ}$ , $r_{3} = 4\,km$ and $\theta_{3} = 120^{\circ}$ , then the resulting vector is: