Looking for H and we have A with soh cah toa A and H is in CAH and H =A/c
so it should be 3/cos(25)=<span>3.0266=3.03</span>
One way to find the y int is to sub in 0 for x and solve for y
10x + 9y = 45
10(0) + 9y = 45
9y = 45 ...divide both sides by 9
y = 45/9 which equals 5
Starting from the Pythagorean identity, we deduce
If we plug in the value 7/10 for sin(x), we have
<h3>Answer:</h3>
33
<h3>Explanation:</h3>
The repeating digits of the sum will have a cycle of length 6 (the LCM of 2 and 3). There will be 3 cycles of the 2-digit repeat, and 2 cycles of the 3-digit repeat.
The sum of digits of the cycle of interest is the sum of the digits in 3 cycles of "12" and 2 cycles of "345", thus 3·(1+2) +2(3+4+5) = 9+24 = 33.
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<em>Another approach</em>
You can look at the sum on a per-digit basis. The 2-digit repeat {12} has a sum of 1+2=3, or 3/2 on a per-digit basis. The 3-digit repeat {345} has a sum of 12, or 12/3=4 on a per-digit basis. The sum of the two repeating decimals will have a sum per digit of 3/2 + 4 = 5 1/2. The 6 repeating digits will then have a sum of 6×(5 1/2) = 33.
Answer:
I is the 3rd answer
Step-by-step explanation: