For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
Answer:
0.677
Step-by-step explanation:Add up the values in the plan A column. There are 10+12+16 = 38 people who prefer plan A.
Add up the values in the "40-49" row to find that 16+8 = 24 people are ages 40 to 49.
We have 38+24-16 = 46 people who either prefer plan A, are aged 40-49, or fit both descriptions. I subtracted off 16 because those 16 people were counted twice when adding 38 and 24.
An alternative way to get this value of 46 is to add up everything that is in column1 or row 3 (or both). So that would get 10+12+16+8 = 46.
Now add up everything in the table to find out how many people were surveyed total. That would be 10+7+12+15+16+8 = 68 people overall.
The probability of someone liking plan A, or being age 40-49, or both is 46/68 = 0.6765 approximately. Rounding to 3 decimal places gives 0.677
Answer:
<h2> 4(-1+2-3+4-5+6-7+......+1000) = 2000</h2>
Step-by-step explanation:
-1+2 = 1
-3+4 = 1
-5+6 = 1
and so on till -999+1000 = 1
1 .... 1000 - these are 1000 numbers, so
1000:2 = 500 pairs with sum equal 1
4(500•1) = 4•500 = 2000
