How to prove it equal 8?

Mathematics

1 answer:

iogann1982 [59]3 years ago

4 0

Answer:

The answer equals -8

Step-by-step explanation:

Order of Operations: BPEMDAS

FOIL - First, Outside, Inside, Last

Step 1: Write out expression

$(\sqrt{4-3i} -\sqrt{4+3i})^6$

Step 2: Expand

$(\sqrt{4-3i} -\sqrt{4+3i})(\sqrt{4-3i} -\sqrt{4+3i})(\sqrt{4-3i} -\sqrt{4+3i})(\sqrt{4-3i} -\sqrt{4+3i})(\sqrt{4-3i} -\sqrt{4+3i})(\sqrt{4-3i} -\sqrt{4+3i})$

Step 3: FOIL first 2

$(\sqrt{4-3i} -\sqrt{4+3i})^2 = -2$

Step 4: Replace square roots with -2

-2(-2)(-2) = (-2)³ = 8

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==========================================================

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