1. The table has a constant of proportionality of 4, therefore, the perimeter and side length of squares are proportional.
2. Equation for the proportion is, y = 4x.
Perimeter = 48 cm.
<h3>What is the Equation of a Proportional Relationship?</h3>
The equation that defines a proportional relationship is, y = kx, where k is the constant of proportionality between variables x and y.
1. For the table given:
y = perimeter
x = side length
k = constant of proportionality = 8/2 = 16/4 = 24/6 = 4.
Since k is the same all through, the equation can be modelled as y = 4x, which means the perimeter and side length of squares are proportional.
2. Using the equation, y = 4x,the perimeter (y) of a square when its side length is 12 (x) is:
y = 4(12)
y = 48 cm.
The perimeter (y) of the square is: 48 cm.
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Answer:
7
Step-by-step explanation:
The initial value is another name for the y-intercept. This equation is written in point slope form (y=mx+b). And before you think y-intercept means y, right? No that is incorrect, I got that wrong in the beginning too ;)
y=mx+b
y=8x+7
b in the point slope form equation is always the initial value or y-intercept or whatever people call it. So what substitutes b out here? 7. So 7 is the initial value!
:) Hope you understand now! Have a good day!
Answer:
For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.
Step-by-step explanation:
The problem states that the monthly cost of a celular plan is modeled by the following function:
In which C(x) is the monthly cost and x is the number of calling minutes.
How many calling minutes are needed for a monthly cost of at least $7?
This can be solved by the following inequality:
For a monthly cost of at least $7, you need to have at least 100 calling minutes.
How many calling minutes are needed for a monthly cost of at most 8:
For a monthly cost of at most $8, you need to have at most 110 calling minutes.
For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.
Answer: 5 km walking and 30 km by bus
Step-by-step explanation:
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?
walking - 5km/h bus - 60km/h
distance walking - d₁ distance bus - d₂
time walking - t₁ time bus - t₂
d₁ + d₂ = 35
t₁ + t₂ = 1.5
v = d/t
vwalking = d₁/t₁
5 = d₁/t₁ ⇒ d₁ = 5t₁
vbus = d₂/t₂
60 = d₂/t₂ ⇒ d₂ = 60t₂
d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35
_________________________
5t₁ + 60t₂ = 35
t₁ + t₂ = 1.5 (*-5)
5t₁ + 60t₂ = 35
-5t₁ -5t₂ = -7.5 (+)
__________________________
55t₂ = 27.5
t₂ = 27.5/55 = 0.5 h
t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h
d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km
d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km
I hope this helps you
regular hexagon =6 equilateral triangle
Area=6.(10.20/2)
Area=600
