Plug 4 in for every x
(3*4)-4=8
(4^2)-1=15 [(4^2) is 4*4]
(2*(4^2))-15= 15 [because of PEMDAS the exponent comes first and then multiply by 2 then subtract]
Perimeter is the sum of the lengths so add up all the sides from above
8+15+15=38
Answer:
56% ≤ p ≤ 70%
Step-by-step explanation:
Given the following :
Predicted % of votes to win for candidate A= 63%
Margin of Error in prediction = ±7%
Which inequality represents the predicted possible percent of votes, x, for candidate A?
Let the interval = p
Hence,
|p - prediction| = margin of error
|p - 63%| = ±7%
Hence,
Upper boundary : p = +7% + 63% = 70%
Lower boundary : p = - 7% + 63% = 56%
Hence,
Lower boundary ≤ p ≤ upper boundary
56% ≤ p ≤ 70%
Answer: Pink choice: y= -6x -2
Step-by-step explanation:
In order to be parallel, the slope must be the same. You find the slope as the number or fraction connected to x. <em>("co-efficient" of x in math talk)</em>
In the given equation, that is -6. (So that knocks out the first two choices)
The other thing to look at is the y-value of the given coordinate,(-1,4)
<em>(The y-value is the second number in the coordinate (x.y) is the pattern)</em>
and compare it to the the last number in the equations in the choices and Here the Yellow choice has y= -6x + 4 so this line can't pass through the coordinate given, because +4 in this equation is where the line crosses the y-axis. ("y-intercept" in math talk) So yellow choice is out!
The attachment shows what the graphs of the choices look like.
The black line is the correct answer. The given coordinate (-1,4) is the labeled red spot. The blue line is the given equation. (You can see where it "intercepts the y-axis on the +3) And the green line also has the -6 slope, but misses the point and intercepts the y-axis at 4.)
I hope the diagram and explanation helps you understand better. It can be confusing.
The answer is x= -6/7<span><span></span></span>
Answer:
Step-by-step explanation:
Ths sum of angle S,T,U is 180°. So,
10x-5 + 2x+4 + x-14 = 180
SOlve for x, and then you can find angle S.