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Lunna [17]
3 years ago
5

Write an equation in point-slope form of the line through these given points.I need separate answers for each problem, thx

Mathematics
1 answer:
andrew-mc [135]3 years ago
7 0

I like point point form because it doesn't fail in the no slope case.  The line through (a,b) and (c,d) is

(c-a)(y-b) = (d-b)(x-a)

Point slope form is almost the same,

y - b = \dfrac{d-b}{c-a} (x-a)

1. (a,b)=(4,0),(c,d)=(-2,1)

y - 0 = (1 - 0)/(-2 - 4) (x - 4)

Answer: y = (-1/6)(x-4)

2.

y - -2 = (3 - -2)/(5 - -3) (x - -3)

Answer: y + 2 = (5/8) (x+3)

3.

y - 1 = (4 - 1)/(3 - -5) (x - -5)

Answer: y - 1 = (3/8) (x+5)

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24/7

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Domain:
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Range:
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Find the variables.<br> (2x)"<br> 54<br> x=
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Use a given information to create equation for the rational function. The function is written in factored form to help see how t
Mars2501 [29]

Recall that a rational function:

\frac{P(x)}{Q(x)},

has a vertical asymptote at x₀ if and only if:

Q(x_0)=0.

Also, the roots of the above rational function are the same as P(x).

Since the rational function has a vertical asymptote at x=-1, we get that its denominator must be:

Q(x)=x+1\text{.}

Since the rational function has a double zero at x=2 we get that its numerator must be of the form:

P(x)=k(x-2)(x-2)\text{.}

Finally, since the rational function has y-intercept at (0,2) we get that:

2=\frac{P(0)}{Q(0)}=\frac{k(0-2)(0-2)}{0+1}\text{.}

Simplifying the above equation we get:

\begin{gathered} \frac{k(-2)(-2)}{1}=2, \\ 4k=2. \end{gathered}

Dividing the above equation by 4 we get:

\begin{gathered} \frac{4k}{4}=\frac{2}{4}, \\ k=\frac{1}{2}\text{.} \end{gathered}

Therefore, the rational function that satisfies the given conditions is:

f(x)=\frac{\frac{1}{2}(x-2)(x-2)}{x+1}\text{.}

Answer:

The numerator is:

\frac{1}{2}(x-2)(x-2)

The denominator is:

(x+1)

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