Answer:
1, 17, 33, 49
Step-by-step explanation:
given the first term is 1 then the next 3 terms are
1 + d, 1 + 2d, 1 + 3d ( d is the common difference )
the sum of the first 4 terms is 100 , then
1 + 1 + d + 1 + 2d + 1 + 3d = 100 , that is
4 + 6d = 100 ( subtract 4 from both sides )
6d = 96 ( divide both sides by 6 )
d = 16
1 + d = 1 + 16 = 17
1 + 2d = 1 + 2(16) = 1 + 32 = 33
1 + 3d = 1 + 3(16) = 1 + 48 = 49
the first 4 terms are
1, 17, 33, 49
Hey there!
One way to do this is find all the factors of 6 and then see which pair fit the requirements.
The factors of 6 are 1, 2, 3, and 6. (Note: There can be negative factors, but I am going to leave them out since it is asking for positive integers.)
You can find them by asking if each number can go into 6.
1, 2, 3, and 6 all go into 6, while 4 and 5 do not.
The requirements we have is that they must be consecutive <u>and</u> have a product of 6.
Consecutive means right after one another.
The only numbers that fit this are 2 and 3.
2 x 3 = 6
Hope this helps!
Answer: x=16/17
Step-by-step explanation: 56=34x+24 34x+24−24=56−24 34x/34=32/34/2/2
x=16/17
