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nordsb [41]
3 years ago
8

Help me and ill mark branilest for first person to answer CORRECTLY. A histogram is being made for the following list of data. I

f the length of each interval is going to be 5, what will be the frequency of the second interval?
78, 92, 98, 87, 86, 72, 92, 81, 86, 92
a.1
b.2
c.3
d.4
Mathematics
1 answer:
kolezko [41]3 years ago
5 0
So to put them in intervals of 5 you would have:
70-74
75-79
80-84
85-89
90-94
95-99
In these intervals you would have:
70-74: 72
75-79: 78
80-84: 81
85-89: 86, 86, 87
90-94: 92, 92, 92
95-99: 98

The second interval is 75-79 where there is only one number. Therefore the frequency will be 1.
The correct answer is A. Hope this helps! :)
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zepelin [54]
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3 years ago
Write each as a decimal. Round to the thousandths place.<br> 9) 78.4%<br> 10) 29%<br> Help
fomenos

Answer:

(a) 78.4\% = 0.784

(b) 29\% =0.290

Step-by-step explanation:

Required

As a decimal to nearest thousandth

Solving (a): 78.4%

78.4\%

Express as fraction

78.4\% = \frac{78.4}{100}

Solve fraction

78.4\% = 0.784 ----- This is already in thousandth place

Solving (b): 29%

29\%

Express as fraction

29\% =\frac{29}{100}

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3 years ago
The midpoint of CD is M=(1, 2). One endpoint is C = (6, -2).
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Answer: Endpoint = (-4,6)

Step-by-step explanation:

To find any endpoint use the formula \frac{x_1+x_2}{2} = Xmp    \frac{y_1+y_2}{2} =Ymp

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multiply each by 2  to simplify

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6+x_{2} = 2                          -2+y_{2} = 4  =  

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To check use the Midpoint formula

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√8

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notsponge [240]
The area of the cross-section is 169 sq. cm. 

That is the correct answer to this problem
5 0
3 years ago
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