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3 years ago

NEED HELP ASAP WILL GIVE BRAINLEST... 30 POINTS!!!!!

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

7 0

Yep the answer is 4 over 16

Iteru [2.4K]3 years ago

4 0

Answer:

4 0ver 16

Step-by-step explanation:

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What is the measure of b?

jolli1 [7]

Answer:

16.5

Step-by-step explanation:

8 0

3 years ago

What is the cube root of 216x^9y^18?

PilotLPTM [1.2K]

Answer:

The cube root of given expression is $6x^3y^6$ .

Step-by-step explanation:

The given expression is

$\sqrt[3]{216x^9y^{18}}$

It can be written as

Use the exponent property: $a^{mn}=(a^m)^n$

$\sqrt[3]{216x^9y^{18}}=\sqrt[3]{6^3(x^3)^3(y^6)^{3}}$

$\sqrt[3]{216x^9y^{18}}=\sqrt[3]{(6x^3y^6)^{3}}$

$\sqrt[3]{216x^9y^{18}}=6x^3y^6$

Therefore the cube root of given expression is $6x^3y^6$ .

8 0

3 years ago

What is the volume of the can below? Use Pi = 3.14 and round your answer to the nearest tenth. A cylinder with height 96 millime

Serga [27]

Answer:

$328,268 mm^3$

Step-by-step explanation:

The can in this problem has a cylindrical shape. The volume of a cylinder can be calculated with the following formula:

$V=\pi r^2 h$

where

r is the radius of the base of the cylinder

h is the height of the cylinder

In this problem we have:

h = 96 mm is the height of the can

d = 66 mm is the diameter of the can

So the radius of its base is

$r=\frac{d}{2}=\frac{66}{2}=33 mm$

And therefore, the volume of the can is:

$V=\pi (33)^2 (96)=328,268 mm^3$

7 0

3 years ago

Read 2 more answers

A boat is pulled toward a dock by means of a rope wound on a drum that is located 6 ft above the bow of the boat. If the rope is

Monica [59]

Answer:

Step-by-step explanation:

Given that:

The height of the dock (h) = 6

Let represent d to be the distance between the boat and the dock

Let the length of the rope between the boat and the drum be denoted by (l)

Then, the rate of change for the length of the rope be:

dl/dt = -5 ft/s

Using Pythagoras rule to determine the relationship between these values, we have:

$l^2 = h^2 +d^2$

$l^2 = 6^2 + d^2$

$l^2 = 36 + d^2$

We relate to: $2l * \dfrac{dl}{dt} = 2d* \dfrac{dd}{dt}$

From the question;

l = 34,

So to find $\dfrac{dd}{dt}$ , we get;

$d = \sqrt{l^2 - 36}$

$d = \sqrt{34^2 - 36}$

$d = \sqrt{1156- 36}$

$d = \sqrt{1120}$

d = 33.46

So, we have:

$\dfrac{dd}{dt}= \dfrac{l}{d} \times \dfrac{dl}{dt}$

$\dfrac{dd}{dt}= \dfrac{34}{33.46} \times - 5$

$\dfrac{dd}{dt}= 1.016 \times - 5$

$\dfrac{dd}{dt}=-5.08 \ ft/sec$

4 0

3 years ago

Kobe's overtime pay is $5 an hour more than his regular pay. He worked 8 hours at his regular wage and 3 hours at his overtime w

Fofino [41]

Answer: $9

Step-by-step explanation: 9•8=72

9+5=14

14•3=42

42+72=114

5 0

3 years ago

Read 2 more answers