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3 years ago

Geometry Question find the area of the circle

Mathematics

2 answers:

olasank [31]3 years ago

8 0

Formula for the area of a circle is Pi*radius squared
So, we do Pi*2^2 which is 12.57

Phoenix [80]3 years ago

3 0

Answer:

4π cm²

Step-by-step explanation:

The radius of this circle is half the diameter, that is, half of 4 cm, or 2 cm.

Then the area of the circle is A = πr² => A = π(2 cm)² = 4π cm²

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A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
Then for the x direction it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, for the y direction, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

8 0

3 years ago

PLEASE HELP ME, ITS DUE RN

madam [21]

Answer:

here you go

Step-by-step explanation:

35+a+b+c=270

35+a=90

a+b=180

35+90+c=180

4 0

3 years ago

Prove that cos^4∆ - sin^4∆ = 2cos^2∆ - 1

GarryVolchara [31]

$\cos^{4} x-\sin^{4} x\\\\=(\cos^{2} x+\sin^{2} x)(\cos^{2} x-\sin^{2} x)\\\\=\cos^{2} x-\sin^{2} x\\\\=\cos^{2} x-(1-\cos^{2} x)\\\\=2\cos^{2} x-1$

3 0

2 years ago

John was given the equation 4(2a + 3)= -3(a - 1) + 31 - 11. Some steps an their reasons have already been completed. State a pro

cestrela7 [59]

Answer:

- Disitributive property.

- Addition property of equality.

Step-by-step explanation:

The complete exercise is attached.

For this exercise you need to remember the following properties:

1. The Distributive property states that:

$c(a+b)=ac+bc\\\\c(a-b)=ac-bc$

2. The Addition property of equality states that:

$If\ a=b\ then\ a+c=b+c$

Then, given the equation:

$4(2a + 3)= -3(a - 1) + 31 - 11a$

You can identify that the first property John used was the Distributive property:

$(4)(2a) + (4)(3)= (-3)(a) +(-3)(- 1) + 31 - 11a\\\\8a+12=-3a+3+31-11a$

After combining like terms, you can identify that the next property he applied was the Addition property of equality, adding $14a$ to both sides of the equation: