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Vladimir [108]
4 years ago
10

Please help!!!

Mathematics
1 answer:
Ratling [72]4 years ago
8 0

x = 3

2x + y - z = 3 → (1)

- x + y + 2z = 0 → (2)

3x + 2y + z = 9 → (3)

we require to eliminate the y and z terms from the equations

(1) + (3) : 5x + 3y = 12 → (4)

multiply (1) by 2

4x +2y - 2z = 6 → (5)

(2) + (5) : 3x + 3y = 6 → (6)

(4) - (6) : 2x = 6 ⇒ x = 3


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Can you please help. Evaluate angles d and e, giving reasons for your answer. ​
garri49 [273]

Answer:

<d = 25 degrees and <e = 130 degrees

Step-by-step explanation:

We have a vertical angle, so the opposite sides of this angle are the same. This means that the angle opposite to 25 degrees also measures 25 degrees. We have one angle of the triangle. Since the triangle is isosceles, the angle d is the same as 25 degrees.

<d = 25 degrees

The interior angles of a triangle add up to 180 degrees, and we now have 2 angles, so:

<e = 180 - 25 - d

<e = 155-25

<e = 130 degrees

4 0
3 years ago
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Which of the following is a radical equation?
m_a_m_a [10]

Answer:

2

Step-by-step explanation:

because it's for the point s

8 0
2 years ago
3/4m + 12 = 36 (this is a Two-Step Equation btw)
elena-s [515]
Hey! Sorry if my answer comes late, I'm going to try and explain the problem to you. 

So first you subtract 12 from 36, getting 24.

Now, you have to figure out what m is since 3/4 of it is 24. What is 24 3/4 of?

32.

So, the answer is m = 32
3 0
3 years ago
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I honestly don’t get how to solve this
ruslelena [56]

Answer:

Two other possible measure ments of AD and AE are

(a)  Let AD = 4 units  and AE = 6 units.

(b )Let AD = 2 units  and AE = 3 units,

Step-by-step explanation:

In ΔABC, given

AB = 8 units,    BC  = 9 units,           AC = 12 units,

D is on AB       and   E is on AC

Now, when AD = 6 and AE = 9, both  ΔABC and ΔADE are similar.

Also, DB = 8 units - 6 units  = 2 units,

        EC = 12 units - 9 units   =  3 units

⇒\frac{AD}{DB}  = \frac{AE}{EC}  =  3

To adjust the points D and E in such a way,  triangles REMAIN SIMILAR.

(a)  Let AD = 4 units  and AE = 6 units

  Then,  DB = 8 units -  4 units  = 4 units,

              EC = 12 units - 6 units   =  6 units

⇒\frac{AD}{DB}  =  \frac{4}{4} = 1 ,  \\ \frac{AE}{EC}  =    \frac{6}{6}   = 1

⇒\frac{AD}{DB}  =  \frac{AE}{EC}  = 1

Hence,   ΔABC and ΔADE are similar.

(b)  Let AD = 2 units  and AE = 3 units

 Then,  DB = 8 units -  2 units  = 6 units,

              EC = 12 units - 3 units   =  9 units

⇒\frac{AD}{DB}  =  \frac{2}{6} =  \frac{1}{3} ,  \\ \frac{AE}{EC}  =    \frac{3}{9}   =  \frac1}{3}

⇒\frac{AD}{DB}  =  \frac{AE}{EC}  =\frac{1}{3}

Hence,   ΔABC and ΔADE are similar.

4 0
3 years ago
Help PLZZ NO FILES NO FILES
finlep [7]

Answer:

A.) you multiply the 3 and 2

5 0
3 years ago
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