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dsp73
3 years ago
6

For an angle theta with the point (-5, -12) on its terminating side, what is the value of cosine?

Mathematics
2 answers:
Fantom [35]3 years ago
6 0
-5 is the adjacent side, -12 is the opposite side, the hypotenuse is 13
Cos = adjacent/hypotenuse
Cos = -5/13
The answer is C. 
FrozenT [24]3 years ago
4 0
The answer is C. .......................
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kakasveta [241]

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5 0
3 years ago
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
Each of the cats in a pet store was weighed. Here are their weights (in pounds):
Gennadij [26K]

Answer:

Mean: 7.8

Median: 7

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP ASAP LOTS OF POINTS AND BRAINIEST!
nikdorinn [45]
Answers: See each part below.

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8k = 6
k = 0.75

4)  To find the lengths of the sides of the landmark, just change the mm into cm and use the scale factor for each.

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7 0
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The variable is x. Find a equation with x with one of the numbers. Then the answer will be x=blank
Nataly_w [17]
X=54 you do 331-7=324 the do 324/6=54 the end hope this helps
7 0
3 years ago
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