we can always find the x-intercept of any equation by simply setting y = 0, so let's do so
![\bf 4x+3y=36\implies 4x+3(\stackrel{y}{0})=36\implies 4x=36\implies x=\cfrac{36}{4}\implies x = 9 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (9~~,~~0)~\hfill](https://tex.z-dn.net/?f=%5Cbf%204x%2B3y%3D36%5Cimplies%204x%2B3%28%5Cstackrel%7By%7D%7B0%7D%29%3D36%5Cimplies%204x%3D36%5Cimplies%20x%3D%5Ccfrac%7B36%7D%7B4%7D%5Cimplies%20x%20%3D%209%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%289~~%2C~~0%29~%5Chfill)
Answer:
Fewer than means that something is less than another thing. For example, the number 2 is fewer than the number 4. There's also this cool symbol that you can use instead of writing the words 'fewer than'. You could say for example 2<4. A fun way to remember which way the symbol points is to imagine it like an alligator, the number 2 is trying to eat the number 4 to grow!
Step-by-step explanation:
Hope this helps!
Weight of an grapefruit=weight of an orange+8% weight of an orange
weight of an apple=weight of an orange -10% weight of an orange
a.<span>By what percentage is the grapefruit heavier than the apple?
We should find the connection between grapefruit and an apple. We know the connection between the weight of a grapefruit and an orange, we know the connection between an orange and an apple, so this means we know the connection between a grapefruit and an apple.
</span>
weight of an grapefruit=weight of an <span>orange+8% weight of an orange
</span>weight of an orange=weight of an apple<span> +10% weight of an apple
</span>
-> weight of an grapefruit=weight of an apple+10% weight of an apple + 8%(weight of an apple+10% weight of an apple)= weight of an apple + 18% weight of an apple + 2% weight of an apple= <span>weight of an apple + 20% weight of an apple
</span><span>b.By what percentage is the apple lighter than the grapefruit?
</span>weight of an grapefruit=weight of an apple + 20% weight of an apple<span>
</span>
-> The apple ts 20% lighter than the grapefruit.
Answer:
A. Sinea spends $26 on games, she wants to keep the same ratio, how much does she spend on souvenirs?
A- (snacks- 16.25) (games- 26) (souvenirs- 39)
B. Ren spends $5 on souvenirs, he wants to keep the same ratio, how much does he spend on snacks
B- (snacks- 2.5) (games- 2) (souvenirs- 5)
C. Both spend $40 on snacks, they want to keep their original ratio, who spends more on souvenirs?
C. Ratios
Sinea- (snacks- 40) (game- 64) (souvenirs- 96)
Ren- (snacks- 40) (game- 32) (souvenirs- 80)
Answer and Step-by-step explanation:
