Question

In this diagram, BAC~ EDF. if the area of BAC = 6 in, what is the area of EDF.

Answer 1

Answer:

2.7 square inch

Step-by-step explanation:

$\triangle BAC \sim \triangle EDF... (Given)$

$\therefore$ By area of similar triangle theorem:

$\frac{A(\triangle BAC)}{A(\triangle EDF)} = \frac{BC^2}{EF^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{3^2}{2^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{9}{4} \\\\\therefore A(\triangle EDF) = \frac{4\times 6}{9} \\\\\therefore A(\triangle EDF) = \frac{24}{9} \\\\\therefore A(\triangle EDF) = 2.6667\\\\\huge \purple {\boxed {\therefore A(\triangle EDF) = 2.7\: in^2}}$