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Pavlova-9 [17]
1 year ago
10

What is the value of a?

Mathematics
1 answer:
Anna007 [38]1 year ago
5 0

Answer:

15 units

Step-by-step explanation:

By using the Pythagoras Theorem,

C^2 = A^2 + B^2

Substitute in the given values,

25^2 = a^2 + 20^2

625 = a^2 + 400

625 - 400 = a^2 + 400 - 400

a^2 = 225

a =  \sqrt{225}

= 15

Hope this too helped! ^^

I'd recommend watching a video or two on the topic of Pythagoras Theorem, if this explanation isn't clear enough.

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A concession stand at an athletic event is trying to determine how much to sell cola and iced tea for in order to maximize reven
Cerrena [4.2K]

Solution :

Demand for cola : 100 – 34x + 5y

Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

x(100 – 34x + 5y) + y(50 + 3x – 16y)

R(x,y)  = $100x-34x^2+5xy+50y+3xy-16y^2$

$R(x,y) = 100x-34x^2+8xy+50y-16y^2$

In order to maximize the revenue, set

$R_x=0, \ \ \ R_y=0$

$R_x=\frac{dR }{dx} = 100-68x+8y$

$R_x=0$

$68x-8y=100$  .............(i)

$R_y=\frac{dR }{dx} = 50-32x+8y$

$R_y=0$

$8x-32y=-50$  .............(ii)

Solving (i) and (ii),

4 x (i)    ⇒       272x - 32y = 400

     (ii)   ⇒   (-<u>)     8x - 32y = -50   </u>

                        264x        = 450

∴   $x=\frac{450}{264}=\frac{75}{44}$

     $y=\frac{175}{88}$

So, x ≈  $ 1.70      and    y = $ 1.99

    R(1.70, 1.99) = $ 134.94

Thus, 1.70 dollars per cola

          1.99 dollars per iced ted to maximize the revenue.

Maximum revenue = $ 134.94

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Answer:

Radius: 8

Circumference: 50.27

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