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NeX [460]
3 years ago
8

Write the equation of the line in slope - intercept form that passes through (3,5) with a slope of 1

Mathematics
1 answer:
Zarrin [17]3 years ago
4 0

Answer:

y= x+2

Step-by-step explanation:

You use this formula     y-y1 =m (x-x1)

you are given (3,5)

so you put the numbers in the formula. And where there is m is where you put the slope which is 1

y - 5 = 1(x-3)

y-5 =x -3

+5         +5

y=x +2

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Solve for x. 2/x+2 + 1/5 = 6/x+5
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3 years ago
If (x-y)^2=71 and x^2+y^2=59 what is the value of xy?
Lena [83]
Solve the equations
first one
take the sqrt of both sides
x-y=√71
add y to both sides
x=y+√71
sub y+√71 for x in other part


(y+√71)²+y²=59
y²+2y√71+71+y²=59
2y²+2y√71+71=59
minus 59 both sides
2y²+2y√71+12=0
factor out 2
2(y²+y√71+6)=0
use quadratic equation or something
y=\frac{- \sqrt{71}- \sqrt{47}  }{2} and \frac{- \sqrt{71}+ \sqrt{47}  }{2}

sub those for x

x=y+√71
note: √71=(2√71)/2

x=\frac{- \sqrt{71}- \sqrt{47}  +2\sqrt{71}}{2} ,\frac{\sqrt{71}- \sqrt{47}}{2}
or
x=\frac{- \sqrt{71}+ \sqrt{47}  +2\sqrt{71}}{2} ,\frac{\sqrt{71}+ \sqrt{47}}{2}

xy=\frac{\sqrt{71}- \sqrt{47}}{2}  times \frac{-\sqrt{71}- \sqrt{47}}{2} or \frac{\sqrt{71}+ \sqrt{47}}{2}  times \frac{-\sqrt{71}+ \sqrt{47}}{2}

the result is -6 both times

xy=-6
5 0
4 years ago
HELP ASAP PLEASEEE!!!!!!!!!
Sergio [31]

Answer:

all the answer choices are correct

Step-by-step explanation:

reflections & rotations dont change any of the angle measures

8 0
2 years ago
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