What is the cross section formed by the cube and the plane containing the diagonals of a pair of opposite faces?

1 answer:

3 0

It will be a square with the dimensions of the a diagonal of any of the faces...

$A=\sqrt{2x^2}^2$

Which is just 2x^2

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docker41 [41]

First do $70(4). That would equal $280. Then do $280+$40=$320

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gulaghasi [49]

The answer is scalene

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Furkat [3]

No I do not know how to do this

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Oksana_A [137]

51.400 is the answer ☺

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Allisa [31]

The answer is b, or 84ft squared. To find the area of a rectangle, you multiple the length by the width. So you multiply 10.5 by 8, which equals 84.

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