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coldgirl [10]
2 years ago
5

Which expression is equivalent to 6 x p +3

Mathematics
2 answers:
enot [183]2 years ago
6 0

Answer:

3 + (px6)

Step-by-step explanation:

hope this helps

Virty [35]2 years ago
3 0

Answer:

3+(p.6)

Step-by-step explanation:

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Identify the percent increase in total sales and the percent increase in sales of trench coats. Then find which percent of
Ilya [14]

Answer:

Answer b: Sales of trench coats increased 8.3 percentage points faster than total coat sales.

Step-by-step explanation:

First add all the sales for 2006, and do the same for the 2007 sales, so we can compare both total sales numbers:

For 2006 we have:

103+297+210+213+137 = 960 total sales

For 2007 we have:

127+223+210+285+259 =  1104 total sales

The percent increase is calculated as the difference between the final value minus the original value, divided by the original value and multiplied by 100:

For the total number of coats we have that the percent increase is: \frac{1104-960}{960} * 100= 15%

For the trench coats (which went from 103 sales tp 127 sales) we have the following percent increase: \frac{127-103}{103} * 100= 23.3%

Therefore, the percent increase in trench coats was larger than the percent increase in total sales by:

23.3 % - 15% = 8.3%

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A 9-foot roll of wrapping paper costs $10.26 . What’s the price per yard?
Strike441 [17]

Answer:

3.42 per yard

Step-by-step explanation:

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The function of (x) varies directly with x^2, and f(x)=96 when x=4 what is the value of f(2)
makkiz [27]
\bf \qquad \qquad \textit{direct proportional variation}
\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------

\bf \textit{f(x) varies directly with }x^2\qquad f(x)=kx^2
\\\\\\
\textit{we also know that }
\begin{cases}
f(x)=96\\
x=4
\end{cases}\implies 96=k(4)^2\implies 96=16k
\\\\\\
\cfrac{96}{16}=k\implies 6=k\qquad therefore\qquad \boxed{f(x)=6x^2}
\\\\\\
\textit{now, when }\stackrel{f(2)}{x=2}\textit{ what is \underline{f(x)}?}\qquad f(2)=6(2)^2
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Need help please!!!!
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