Can someone explain me this question
1 answer:
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Answer:
1. a. Please find attached, the diagram for the first circle with radius = 3 cm
b. Please find attached, the diagram for the second circle with diameter = 3 cm
2. The similarities are;
a) Both circles can be described by a point and a radius or a diameter
The differences are;
a) The length of the radiuses are different for the two circles (3 cm and 1.5 cm)
b) The circumferences of the two circles are different
c) The area covered by the two circles are different
3. The circumference of the circle with radius equal to 3 cm is larger than the circumference of the circle with diameter equal to 3 cm
4. The circumference to diameter ratio of the circle with radius = 3 cm is π
The circumference to diameter ratio of the circle with diameter = 3 cm is π
Both circles have equal circumference to diameter ratio given that the circumference = π × The diameter
Step-by-step explanation:
1. a. The radius length of the first circle = 3 cm
The diagram for the first circle with radius 3 cm is attached
b. The diameter length of the second circle = 3 cm
The diagram for the second circle with diameter 3 cm is attached
2. The similarities are;
a) Both circles can be described by a point and a radius or a diameter
The differences are;
a) The length of the radiuses are different for the two circles (3 cm and 1.5 cm)
b) The circumferences of the two circles are different
c) The area covered by the two circles are different
3. The circumference of the circle with radius equal to 3 cm is 2 × π × 3 = 6·π cm
The circumference of the circle with diameter equal to 3 cm is π × 3 = 3·π cm
Therefore, the circumference of the circle with radius equal to 3 cm is larger than the circumference of the circle with diameter equal to 3 cm
4. The circumference to diameter ratio of the circle with radius = 3 cm is 6·π cm/(2 × 3 cm) = π
The circumference to diameter ratio of the circle with diameter = 3 cm is 3·π cm/(3 cm) = π.
Both circles have equal circumference to diameter ratio given that the circumference = π × The diameter.
