Answer:
Travis should pick to play the hat game.
Step-by-step explanation:
You would need to evaluate the probablity of winning in each option
Option 1 (rolling die)
p(roll 2 or 3)=2/6
p(roll 2 or 3)=1/3=.33
Option 2 (pick letters)
p(pick A or B) = 2/5
p(pick A or B) = .4
.33<.4
Since option 2 with picking letters has a higher chance of winning, then Travis should play the second game to win the goldfish as a higher chance of winning makes it easier for him to win the prize.
Answer:
262ft
Step-by-step explanation:
Take a picture of the table
Let <em>f(x)</em> = (<em>x</em> ² - 1)³. Find the critical points of <em>f</em> in the interval [-1, 2]:
<em>f '(x)</em> = 3 (<em>x</em> ² - 1)² (2<em>x</em>) = 6<em>x</em> (<em>x </em>² - 1)² = 0
6<em>x</em> = 0 <u>or</u> (<em>x</em> ² - 1)² = 0
<em>x</em> = 0 <u>or</u> <em>x</em> ² = 1
<em>x</em> = 0 <u>or</u> <em>x</em> = 1 <u>or</u> <em>x</em> = -1
Check the value of <em>f</em> at each of these critical points, as well as the endpoints of the given domain:
<em>f</em> (-1) = 0
<em>f</em> (0) = -1
<em>f</em> (1) = 0
<em>f</em> (2) = 27
So max{<em>f(x)</em> | -1 ≤ <em>x </em>≤ 2} = 27.
