A% x 50 = 35
a/100 x 50 = 35
a/2 = 35
a = 70
First we'll require the derivative (slope) function.
f'(x) = 6x + 1
Next evaluate the derivative function @ x = -2
f'(-2) = 6(-2) + 1
f'(-2) = -11
Thus the slope of the tangent line @ x = -2 is m = -11
Now we can use either y = mx + b or y - y1 = m(x - x1) to find the tangent equation.
y - 4 = -11(x - (-2))
y - 4 = -11(x + 2)
y - 4 = -11x - 22
y = -11x - 22 + 4
Thus
y = -11x - 18 or 11x + y + 18 = 0 is the equation of the required tangent.
Answer:
B
Step-by-step explanation:
Answer:
The average speed of the 747 was of 580 miles per hour.
Step-by-step explanation:
We use the following relation to solve this question:
In which v is the velocity, d is the distance and t is the time.
A small airplane flies 1015 miles with an average speed of 290 miles per hour.
We have to find the time:
1.75 hours after the plane leaves, a Boeing 747 leaves from the same point. Both planes arrive at the same time;
The time of the Boeing 747 is:
Distance of , the velocity is:
The average speed of the 747 was of 580 miles per hour.
Answer:
2t-7
Step-by-step explanation:
2(t-4)+1
2t -8+1
2t - 7