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Margarita [4]
3 years ago
3

In printmaking, the origination point from which a print is derived is known as the __________. The single print taken from one

of these using a printing press is referred to as the ___________ whereas all the identical copies created during a single printing form the ___________. When printing in color, the process of aligning the different plates so that all the colors print perfectly is called the _______.
Computers and Technology
1 answer:
Genrish500 [490]3 years ago
8 0

Answer:

The answer is MATRIX, IMPRESSION, EDITION, and SILKSCREEN PRINTING OR SCREEN PRINTING

Explanation:

In printmaking, the origination point from which a print is derived is known as the MATRIX. The single print taken from one of these using a printing press is referred to as the IMPRESSION, whereas all the identical copies created during a single printing form the EDITION.

When printing in color, the process of aligning the different plates so that all the colors print perfectly is called the SILKSCREEN PRINTING OR SCREEN PRINTING

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A) Write a program that asks the user for the amount of money they will take on holiday and convert this into the equivalent amo
Lelu [443]

def func():

   money = int(input("How much money will you have on holiday? "))

   print("You will have {} euros.".format(int(money * 1.11)))

   money = int(money * 1.11)

   fifty = 0

   twenty = 0

   ten = 0

   five = 0

   while True:

       if money - 50 >= 0:

           fifty += 1

           money -= 50

       elif money - 20 >= 0:

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           money -= 20

       elif money - 10 >= 0:

           ten += 1

           money -= 10

       elif money - 5 >= 0:

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           money -= 5

       if money < 5:

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func()

I hope this helps!

5 0
3 years ago
Write a program that computes the sum of the first tenpositive integers, 1 + 2 + ..+ 10.
Stella [2.4K]

Answer:

#include <iostream>  

using namespace std;

int main()

{

  int sum=0;//taking an integer variable to store the sum with initial value 0..

  for(int i=1;i<=10;i++)//looping from 1 to 10..

  {

      sum+=i;//adding each i in the sum..

  }

  cout<<sum<<endl;//printing the sum..

   return 0;

}

Explanation:

output :- 55

1.I have taken an integer variable sum which is equal to 0.

2.Looping over first ten positive integers.

3.Adding every number to sum.

4.Printing the sum.

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