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3 years ago

Write a description of how a diagram can help you solve 2×40

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

8 0

Draw 40 boxes, and in a separate section draw another 40 boxes.
(If you have the time :) )

Viefleur [7K]3 years ago

7 0

A diagram can help you by just draw 80 boxes.

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Simplify.<br> In e =<br> In e 2x=<br> In 1 =

Shalnov [3]

Answer:

ln e = 1

ln e 2x = 2x

ln 1 = 0

Step-by-step explanation:

ln e

ln(2.718282) = 1

In e 2x

ln(2.718282)(2)x = 2x

ln 1 = 0

5 0

3 years ago

What comes after 3.4 in a pattern when dividing

lutik1710 [3]

What comes after 3.4 im pretty sure its 3.5

5 0

3 years ago

Read 2 more answers

Triangle F G E is shown. Angle F E G is a right angle. The length of hypotenuse F G is 15.2 meters and the length of F E is 9 me

ololo11 [35]

Answer:

<h3>sin(x) = StartFraction 9 Over 15.2 EndFraction</h3>

Step-by-step explanation:

From the triangle given;

The length of hypotenuse FG = 15.2 meter

Since FE is the side facing the angle FGE, then;

the length of FE is opposite = 9 meters

m<FGE = x

According to SOH CAH TOA

sin theta = opp/hyp

sin m<FGE = FE/FG

Substitute the given values

sin x = 9/15.2

Hence the correct answer is sin(x) = StartFraction 9 Over 15.2 EndFraction

3 0

3 years ago

Read 2 more answers

AB and BC form a right angle at point B if A = (-3,-1) and B = (4,4) what is the equation if BC

sergejj [24]

Answer:

$7x+5y-48=0$

Step-by-step explanation:

Refer the attached figure .

We are given a line AB

Point A $=(x_1,y_1) = (-3,-1)$

Point B $=(x_2,y_2) = (4,4)$

Formula for slope 'm' when two points are given :

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting thew values

$m=\frac{4-(-1)}{4-(-3)}$

$m=\frac{5}{7}$

Since we are given that AB is perpendicular to BC

So, By property - perpendicular slopes are negative reciprocals of each other.

$\Rightarrow m_1\times m_2 =-1$

$\Rightarrow \frac{5}{7}\times m_2 =-1$

$\Rightarrow m_2 = \frac{-7}{5}$

So, Slope for line BC : $m_2 = \frac{-7}{5}$

Point B = (4,4)

Formula of equation of line : $y-y_1=m(x-x_1)$

$y-4=\frac{-7}{5}(x-4)$

$5(y-4)=-7(x-4)$

$5y-20=-7x+28$

$7x+5y-20-28=0$

$7x+5y-48=0$

Hence the equation of line BC : $7x+5y-48=0$

5 0

3 years ago

Hey can some one help me out

Archy [21]

I believe the correct situation is C

3 0

3 years ago