We are given an angle of 60° and a side of 15 cm.
We are given the opposite and is looking for the hypotenuse so we will use the sine ratio to find x.
sin = opp/hyp
hyp = 15 / sin 60
hyp = 17.32...
//
We can also use the tangent ratio to find the adjecent and then use pythagorean to find x.
tan = opp/adj
adj = 15 / tan 60
adj = 8.660.....
8.660....² + 15² = 300²
since the square root of 300 is an irrational number, we have to turn it into a mixed radical.
The answer would be the top one.
Answer:
The daily value for saturated fat is 20g.
Step-by-step explanation:
Percentage problems can be solved by rule of three
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
A percentage problem is an example where the relationship between the measures is direct.
The problem states that 1g is 5% of the daily value for saturated fat. The daily value(100%) for saturated fat is x, so:
1g - 5%
xg - 100%
5x = 100

x = 20g
The daily value for saturated fat is 20g.
The value of x, y and z from the system of equation are -1, -8 and 5 respectively.
Data;
- -2x + 6y + 3z = -31
- -3y + 7z = 59
- 2z = 10
<h3>System of Equation</h3>
To solve this problem, we have to solve the system of equation using substitution method.
From equation (iii)

let us substitute the value of z into equation (ii)

Let's substitute the value of x and y into equation (i)

From the calculation above, the value of x, y and z are -1, -8 and 5 respectively.
Learn more on system of equations here;
brainly.com/question/14323743
Answer:
9
Step-by-step explanation:
18/2=9
Oh wait. I am wrong
The domain of the function is \[A \ge0\] If A is negative we get an imaginary number for the radius. This makes sense because the area of a circle cannot be negative.