The quadratic equation cannonball’s path if it was launched with the same velocity, but from the ground instead would be given by:

<h3>What is the quadratic equation for the height of a projectile?</h3>
Considering the gravity, it is modeled by:

In which:
is the initial velocity.
is the initial height.
For this problem, we want:
- The same initial velocity, hence
.
- Launched from the ground, hence
.
Then, the equation is:

More can be learned about quadratic equations at brainly.com/question/24737967
The answer is 0.019 i think
Answer:
C
Step-by-step explanation:
The parent graph of this function is the absolute value, or |x|. However, it is shifted 8 units to the right and 2 units up. Therefore, the equation of this function is y=|x-8|+2, or answer choice C. Hope this helps!
<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em> </em><em>units</em><em>.</em>
<em>please</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> </em><em>full</em><em> </em><em>solution</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>helps</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> assignment</em>
Answer: x=2 - 1/2 x ㏒(16/2953125)
Step-by-step explanation:
- log (28^2) + log(525^-3) + 2x=log(10^4)
- log(28^2 x 1/523^3) + 2x=4
- log(28^2/525^3) + 2x=4
- log (112/75 x 75 x 525) + 2x=4
- log(16/2953125) + 2x=4
- 2x=4-log(16/2953125)
- <u><em>x=2-1/2 x log(16/2953125)</em></u>