Answer:
![x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}](https://tex.z-dn.net/?f=%20x%20%3D%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-4ac%7D%7D%7B2a%7D)
Where a = 2 , b= 3, c= -5, replacing we have this:
![x =\frac{-3 \pm \sqrt{(-3)^2 -4(2)(-5)}}{2*2}](https://tex.z-dn.net/?f=x%20%3D%5Cfrac%7B-3%20%5Cpm%20%5Csqrt%7B%28-3%29%5E2%20-4%282%29%28-5%29%7D%7D%7B2%2A2%7D)
And simplifying we got:
![x = \frac{-3 \pm \sqrt{49}}{4}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B-3%20%5Cpm%20%5Csqrt%7B49%7D%7D%7B4%7D)
And the two solutions are:
![x_1 = \frac{-3+7}{4}= 1](https://tex.z-dn.net/?f=%20x_1%20%3D%20%5Cfrac%7B-3%2B7%7D%7B4%7D%3D%201)
![x_2 = \frac{-3-7}{4}= -\frac{5}{2}](https://tex.z-dn.net/?f=%20x_2%20%3D%20%5Cfrac%7B-3-7%7D%7B4%7D%3D%20-%5Cfrac%7B5%7D%7B2%7D)
And the correct options are:
B and C
Step-by-step explanation:
We have the following equation given:
![2x^2 +3x -5=0](https://tex.z-dn.net/?f=%202x%5E2%20%2B3x%20-5%3D0)
And if we use the quadratic formula given by:
![x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}](https://tex.z-dn.net/?f=%20x%20%3D%5Cfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-4ac%7D%7D%7B2a%7D)
Where a = 2 , b= 3, c= -5, replacing we have this:
![x =\frac{-3 \pm \sqrt{(-3)^2 -4(2)(-5)}}{2*2}](https://tex.z-dn.net/?f=x%20%3D%5Cfrac%7B-3%20%5Cpm%20%5Csqrt%7B%28-3%29%5E2%20-4%282%29%28-5%29%7D%7D%7B2%2A2%7D)
And simplifying we got:
![x = \frac{-3 \pm \sqrt{49}}{4}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B-3%20%5Cpm%20%5Csqrt%7B49%7D%7D%7B4%7D)
And the two solutions are:
![x_1 = \frac{-3+7}{4}= 1](https://tex.z-dn.net/?f=%20x_1%20%3D%20%5Cfrac%7B-3%2B7%7D%7B4%7D%3D%201)
![x_2 = \frac{-3-7}{4}= -\frac{5}{2}](https://tex.z-dn.net/?f=%20x_2%20%3D%20%5Cfrac%7B-3-7%7D%7B4%7D%3D%20-%5Cfrac%7B5%7D%7B2%7D)
And the correct options are:
B and C
To convert to a decimal you divide
8 ÷ 25 = 0.32
0.32 is the decimal
Answer:
The perimeter is ![P=73.12\ cm](https://tex.z-dn.net/?f=P%3D73.12%5C%20cm)
Step-by-step explanation:
we know that
The perimeter of the figure is equal to the circumference of a semicircle
plus the perimeter of a square minus the diameter of the circle
so
![P=\pi r+4(b)-D](https://tex.z-dn.net/?f=P%3D%5Cpi%20r%2B4%28b%29-D)
we have
![r=8\ cm](https://tex.z-dn.net/?f=r%3D8%5C%20cm)
![b=16\ cm](https://tex.z-dn.net/?f=b%3D16%5C%20cm)
![D=16\ cm](https://tex.z-dn.net/?f=D%3D16%5C%20cm)
The diameter of the circle is equal to the length side of the square
substitute
![P=(3.14)(8)+4(16)-16](https://tex.z-dn.net/?f=P%3D%283.14%29%288%29%2B4%2816%29-16)
![P=25.12+64-16](https://tex.z-dn.net/?f=P%3D25.12%2B64-16)
![P=73.12\ cm](https://tex.z-dn.net/?f=P%3D73.12%5C%20cm)
Based on the information given the number of apple trees that are in the orchard are 80 apple trees.
<h3>Number of apple trees in the orchard:</h3>
Using this formula
Number of apple trees=Number of peach trees×Number of pecan trees×Number of apple trees÷Number of peach trees×Number of pecan trees
Let plug in the formula
Number of apple trees=24 peach trees ×5 pecan trees × 4 apple trees÷2 peach trees ×3 pecan trees
Number of apple trees=480÷6
Number of apple trees=80 apple trees
Inconclusion the number of apple trees that are in the orchard are 80 apple trees.
Learn more about number of apple trees that are in the orchard here:brainly.com/question/11642092
Yeah you should try khan academy or Ytube