Answer:
Option B is right
Step-by-step explanation:
We have in a triangle there are some properties inherent.
One is the perpendicular bisectors of all sides are concurrent.
These three concur at a point called the circumcentre of the triangle.
When we draw perpendicular bisector for a side AB, we get that all points on the perpendicular bisector are equidistance from A and B.
When we take the point of intersection of perpendicular bisector of AB and BC, we have the intersecting point S(say) is equidistant from A and B and also from B and C
In short this is equidistant from all 3 vertices and hence is centre of circumcicle of triangle ABC
