Question

What is the value of Left-bracket (two-thirds) Superscript 0 Baseline Right-bracket Superscript negative 3?

Answer 1

Answer:

= 1

Step-by-step explanation:

[(2/3)^0]^-3

= 1/1·1·1

= 1

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Answer 2

Answer:

The value of the expression is 1.

Step-by-step explanation:

The expression is:

$[(\frac{2}{3})^{0}]^{-3}$

Exponent rules:

$a^{0}=1\\\\(a^{m})^{n}=a^{m\times n}\\\\a^{-m}=\frac{1}{a^{m}}$

Simplify the expressions as follows:

$[(\frac{2}{3})^{0}]^{-3}=[1]^{-3}$

            $=\frac{1}{1^{3}}\\\\=\frac{1}{1}\\\\=1$

Thus, the value of the expression is 1.