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Svetach [21]
3 years ago
15

What is the value of Left-bracket (two-thirds) Superscript 0 Baseline Right-bracket Superscript negative 3?

Mathematics
2 answers:
earnstyle [38]3 years ago
5 0

Answer:

= 1

Step-by-step explanation:

[(2/3)^0]^-3

= 1/1·1·1

= 1

Please thank me if correct :)

Vinil7 [7]3 years ago
3 0

Answer:

The value of the expression is 1.

Step-by-step explanation:

The expression is:

[(\frac{2}{3})^{0}]^{-3}

Exponent rules:

a^{0}=1\\\\(a^{m})^{n}=a^{m\times n}\\\\a^{-m}=\frac{1}{a^{m}}

Simplify the expressions as follows:

[(\frac{2}{3})^{0}]^{-3}=[1]^{-3}

            =\frac{1}{1^{3}}\\\\=\frac{1}{1}\\\\=1

Thus, the value of the expression is 1.

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lianna [129]

SimplifyOkie dokie so first things first, you have to get rid of those parentheses! To do this you use the distributive property. -3(x+2) is the same thing as -3(x)+-3(2). that and you get -9=-3x-6. So you want to get x by itself to be able to find what x is, so you add 6 to both sides of the equation to get rid of the -6. So then you get -3=-3x. Then you must divide both sides by the coefficient of x, which would be -3. When you divide both sides by -3 you get -3/-3=x, which is the same thing as 1=x. Hope this helped!

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4 years ago
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Answer:

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Step-by-step explanation:

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