Answer:
The shortcomings or drawbacks of cell theory are: Viruses are considered as acellular entities or organisms that do not have cell machinery, yet they are taken into account as organisms in this cell theory. Matthias Schleiden and Theodor Schwann did not know the mechanism of the cell.
Explanation:
The correct option is this: CELL 2 WILL THE ONE THAT WILL BE ABLE TO ELIMINATE WASTES MOST EFFICIENTLY. This is because it has the highest surface area to volume ratio which facilitates the exchange of materials between a cell and its environment.
The rate of diffusion of materials into and out of the cell depends on the surface area to volume ratio of the cell. The higher this ratio, the higher the rate of diffusion.
Answer:
It is a biological process by which an organism reproduces an offspring who is biologically similar to the organism.
Explanation:
I hope I have cleared ur doubt if not do mention in comment
Answer:
I would probably want to give my child one or two specific traits like intelligence or no inheritable diseases, because I would want my child to have a excellent chance of success in life.
Explanation:
Answer:
The correct answers are A. "crenation", B. "hemolysis", C. "hemolysis", D. "crenation" and E. "neither will occur".
Explanation:
0.9% (m/v) NaCl or 5.0% (m/v) glucose are isotonic solutions at which the cells will not suffer any harmful consequence. A solution with a higher concentration than the isotonic conditions would result in the cells crenation, while a solution with a lower concentration would result in the cells hemolysis. Therefore the consequences of putting the red cells to the solutions stated in the question are as following:
A: 3.21% (m/v) NaCl Solution = crenation (higher than 0.9% (m/v) NaCl)
B: 1.65% (m/v) glucose Solution = hemolysis (lower than 5.0% (m/v) glucose)
C: distilled H2O Solution = hemolysis (lower than 0.9% (m/v) NaCl or 5.0% (m/v) glucose)
D: 6.97% (m/v) glucose Solution = crenation (higher than 5.0% (m/v) glucose)
E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl = neither will occur (equal to 5.0% (m/v) glucose and 0.9% (m/v) NaCl)
