I think its 1/6
I'm not sure tho
u take the bottom and subtract it by the top then multiply
Answer: The speed of car B is 6.44 m/s
Step-by-step explanation:
Let's define:
Sa = Speed of car A.
Sb = Speed of car B.
I assume that at t = 0s, the position of car A is 0m (then at t = 0s, the position of car B is 174m)
Then we can write the positions of each car as:
Pa(t) = Sa*t
Pb(t) = Sb*t + 174m.
We also know that Sa = 2*Sb.
And we know that at t= 27s, car A passes car B.
Then at t = 27s, the positions of both cars must be the same:
Pa(27s) = Pb(27s)
Sa*27s = Sb*27s + 174m.
Now we can replace Sa by 2*Sb (from the above equation)
2*Sb*27s = Sb*27s + 174m
Now we can solve this for Sb.
2*Sb*27s - Sb*27s = 174m
Sb*27s = 174m
Sb = 174m/27s = 6.44m/s.
The speed of car B is 6.44 m/s
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➷ final = original x multiplier
final = 10,000 x 1.065
final = 10650
It is $10650
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Answer:
(a) is true
Step-by-step explanation:
Given
See attachment for box plots
Required
Which of the options is true?
Option A compares the IQR of both plots.
IQR is calculated using:
Where
Lower quartile
Upper quartile
From the attached plots, we have:
Republican
So:
Democratic
So:
We have:
--- Republican
--- Democratic
<em>Hence, (a) is true</em>
The water in the tank is decreasing at a rate of 2 gallons per minute.