If both classes contain 167 students then we add them 167+167= 334
The area of a trapezoid is h(a + b) /2 where h=height and a and b are lengths of the parallel sides.
So here the area is 5 * (5 + 3) / 2
= 5 * 8 / 2
= 20 units^2
The package weighed 16 pounds.
You do 32 divided by 2 and get 16
Let y = 0 to find the zeros.
![x^{2} + 5x + 6 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%205x%20%2B%206%20%3D%200)
We can now split the middle term into factors of 6 that add up to 5.
![x^{2} + 3x + 2x + 6 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%203x%20%2B%202x%20%2B%206%20%3D%200)
Group the first two terms, and group the last two terms, and factorise.
![(x^{2} + 3x) + (2x + 6) = 0](https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2B%203x%29%20%2B%20%282x%20%2B%206%29%20%3D%200)
![x(x + 3) + 2(x + 3) = 0](https://tex.z-dn.net/?f=x%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%20%3D%200)
Group like terms.
![(x + 3)(x + 2) = 0](https://tex.z-dn.net/?f=%28x%20%2B%203%29%28x%20%2B%202%29%20%3D%200)
Now, we know that in order for a zero to occur, either x + 3 = 0 or x + 2 = 0.
Hence, x = -3 and -2 are the zeros in this quadratic.
Answer:
Step-by-step explanation:
5√7²=5√49=9.8