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3 years ago

Lines m and n are parallel.

Mathematics

2 answers:

postnew [5]3 years ago

8 0

Answer:

Step-by-step explanation:

natka813 [3]3 years ago

5 0

Answer:

The angle 1 will be equal to 55°.

Step-by-step explanation:

See the attached diagram.

Here, line m and line n are parallel and line k is the transverse line.

So, from the properties of parallel lines with a transverse line the angle 55° and the angle 1 are corresponding angles and they are equal.

Therefore, angle 1 will be equal to 55°. (Answer)

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How to solve 2a x a x a x3a + b +4b

kodGreya [7K]

Answer:

$6 {a}^{4} + 5b$

Step-by-step explanation:

$2a \times a\times a \times 3 a+ b + 4b \\ 2a \times a = 2 {a}^{2} \\ 2 {a}^{2} \times a = 2 {a}^{3} \\ 2 {a}^{3} \times 3a = 6 {a}^{4} \\b + 4b = 5b$

Therefore the answer is

$6 {a}^{4} + 5b$

3 0

2 years ago

Read 2 more answers

An electrician needs to run a cable from the top of a 40-foot tower to a transmitter box located 30 feet away from the base of

grin007 [14]

The cable should be 50 feet.

If you draw the picture, you will see that you have a right triangle.

Let's just use the Pythagorean Theorem to find the hypotenuse (or cable).

30^2 + 40^2 = c^2
2500 = c^2
50 = c

3 0

3 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

4 0

3 years ago

Find the measure of angle FED and DEN. Thx!!!! :)

Katena32 [7]

Answer:

m<FED=60, m<DEN=120

Step-by-step explanation:

m<FED=60

This is because <GEN and <FED are vertical angles.

Vertical angles are always congruent.

Vertical angles are formed by a pair of intersecting lines, and are the angles directly across from one another.

m<DEN=120

This is because <DEN and <GEN are supplementary.

Supplementary angles add up to 180 degrees.

We know this because a straight line is always 180 degrees.

So:

m<DEN+m<GEN=180

m<DEN+60=180

m<DEN=120

6 0

3 years ago

Amanda is going to rent a truck for one day. There are two companies she can choose from, and they have the following prices. Co

Tema [17]

Answer:

For mileages higher than 80 miles Company A will charge less than Company B

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

Company A charges $111 and allows unlimited mileage.

Company A =111

Company B has an initial fee of $55 and charges an additional $0.70 for every mile driven

Company B = 55+0.70m

Where m is the number of miles.

Company A has to charge less than Company B

a<b

111 < 55+0.70m

Solving for m

111-55 < 0.70 m

56 < 0.70m

56/0.70 < m

80 < m

For mileages higher than 80 miles Company A will charge less than Company B

5 0

3 years ago