All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.
2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30
3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents
4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.
Answer:
15%
Step-by-step explanation:
$40 : 100 = 0,4
1% is $0,4
$6 : 0,4 = 15%
So the percentage is 15%.
The mean is the average, which is the sum of all the numbers divided by the total numbers there are. I will add them up for you, and then work from there.
184 + 192 + 164 + 200 = 740.
There is 740cm total, but now we need to divide by how many students we have. We have 4 students total.
740/4 = 185.
Your average (mean) height of the students is 185cm.
I hope this helps!
Answer:
-3
Step-by-step explanation:
first do -22-2= -24
then do 1/8 of -24= -3
I think the answer is (x-2 ) x ( x+2)
