* 14. Solve. 2y - 1.7= 3.3.<br> y=

What is the answer so confused

suter [353]

Cause a number cube is wack and cant solve nothin bout bowling you gotta use the numbers 6 outta 10

8 0

3 years ago

How to solve 2.925/1-1.00375^(-24)

uysha [10]

Answer:

Look up on the Internet you’re welcome

Step-by-step explanation:

3 0

4 years ago

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELP

Leviafan [203]

Answer:

a=16

Step-by-step explanation:

First of all you subtract both sides by 2 which makes 6-2=a/4 +2-2 which makes 4=a/4. then you multiply both sides by 4, 4x4=a/4 x 4 which makes a= 16 now you check this by putting a into the equation then going 16/4=4 then adding 2, 4+2= 6 then checking if it equals which it does

Would be amazing if you marked brainliest :)

6 0

3 years ago

Read 2 more answers

The box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0 300 600 900 1,200 $1,500 a

kkurt [141]

Answer:

(a) The median estimate is 450.

(b) The first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is 450.

(d) The particular value which is less than 150 or it is more than 1200, is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed.

Step-by-step explanation:

We are given that the box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0, 300, 600, 900, 1,200, 1,500.

(a) As we can see in the box plot that the middlemost data lies between 300 and 600, that means;

Median is given by the average of the two numbers, i.e;

Median = $\frac{300+600}{2}$

= $\frac{900}{2}$ = 450

So, the median estimate is 450.

(b) As we know that the first quartile represents 25% of the data values and the third quartile represents 75% of the data values.

So, from the box plot given; we can observe that the first quartile, $Q_1$ = 300 and the third quartile lies between the values of 600 and 900, i.e;

Third quartile, $Q_3$ = $\frac{600+900}{2}$

= $\frac{1500}{2}$ = 750

So, the first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is given by the following formula;

Interquartile range = Third quartile - First quartile

= $Q_3-Q_1$

= 750 - 300 = 450

(d) From the box plot; it is clear that if the particular value is less than 150 or it is more than 1200, then it is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed because the more values are on the right side of the curve and it skewed towards the right.

4 0

4 years ago

Judy spent 3 hours driving 165 miles She thinks

sasho [114]

Step-by-step explanation:

she drove already 165 miles.

she will reach her destination, if she drives 4 more hours by going 65 miles/hour.

that would mean she would travel

65×4 = 260 miles

in these 4 hours.

so, the total trip is then 165 + 260 = 425 miles.

but what I find strange is that your teacher specified how long it took her to drive the first 165 miles.

as you can see above, it would make no difference for the calculation of the total trip length in miles.

this is either an attempt to confuse us, or the message is that Judy has to achieve an average of 65 miles/hour for the whole trip, and the problem definition was just imperfectly phrased.

if that is the case, then things look a bit different, as her average speed was only 165/3 = 55 miles/hour for the first 3 hours and 165 miles.

so,

(165 + x)/(3 + 4) hours = 65/hour

(165 + x)/7 hours = 65/hour

165 + x = 65 × 7 hours / hour = 65×7 = 455 miles

x = 455 - 165 = 290 miles

she would have to go

290 miles / 4 hours = 72.5 miles/hour

for these next 4 hours (and 290 miles) to reach an overall average speed of 65 miles/hour.

and the total trip would be then

165 + 290 = 455 miles

I am not sure, which your teacher wants here.

65 miles/hour average speed just for the next 4 hours, or to speed up that much for the next 4 hours that the overall trip average is then 65 miles/hour.

again, the phrasing of the problem definition suggests the first case, but the fact that the travel time for the first part of the trip is given could suggest the second case (as this information is not needed for the first case).

6 0

3 years ago

* 14. Solve. 2y - 1.7= 3.3. y=