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2 years ago

Probabilities are __ one.

Mathematics

2 answers:

jeyben [28]2 years ago

6 0

Answer:

Hey!

Your answer is D) ALWAYS EQUAL TO ONE

Step-by-step explanation:

HOPE THIS HELPS!!

VladimirAG [237]2 years ago

3 0

Answer:

Im gonna go with A

Step-by-step explanation:

You might be interested in

Find the common ratio r for the geometric sequence, and use r to find the next 3 terms n 1, 2, 3, 4, 5, 6, 7 f(n) 1,4,16,64

mote1985 [20]

Divide the given terms:

4/1 = 4

16/4 = 4

64/16 = 4

R = 4

The next term is the previous term multiplied by 4.

64 x 4 = 256

256 x 4 = 1024

1024 x 4 = 4096

The next three terms are: 256, 1024, 4096

4 0

2 years ago

List the single-digit divisors of 2100. I really need help

liberstina [14]

Answer:

1, 2, 3, 4, 5, 6, 7

Step-by-step explanation:

Prime factors of 2100 are:

2100 = 2*2*3*5*5*7

The single-digit divisors are:

1, 2, 3, 2*2= 4, 5, 2*3= 6, 7

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Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:

2100/1 = 2100, yes
2100/2 = 1050, yes
2100/3 = 700, yes
2100/4 = 525, yes
2100/5 = 420, yes
2100/6 = 350, yes
2100/7 = 300, yes
2100/8 = 262.5, no
2100/9 = 233.33, no

So all the numbers from 1 to 7

5 0

3 years ago

What is the answer to 29=5a+4

DanielleElmas [232]

29 = 5a + 4
25 = 5a
5 = a

5 0

3 years ago

Read 2 more answers

Can someone help me? I’ll reward points + brainalist

posledela

Step-by-step explanation:

THE ANSWER IS C. 31 INCHES

5 0

2 years ago

Read 2 more answers

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

3 years ago