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adell [148]
4 years ago
6

Which best describes Nosaira's work and answer? Her work is correct, but there is one solution rather than no solution. Her work

is correct and her interpretation of the answer is correct. Her work is incorrect. She distributed incorrectly. Her work is incorrect. She moved terms across the equals sign incorrectly.
Mathematics
2 answers:
LiRa [457]4 years ago
9 0

Answer:

her work is correct but there is one solution rather than no solution

Step-by-step explanation:

  • hmmmmm but the equation is better t there but I think this should be it
  • Assuming the equation was given
Rudik [331]4 years ago
5 0

Answer:

The answer is A or (Her work is correct, but there is one solution rather than no solution.)

Step-by-step explanation:

Just took the quiz and got 100%. Pls mark as brainiest! and hit that THANKS button for appriciation!

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The square of a whole number 'n' lies between 80 and 150. Find all possible values for 'n'.
pychu [463]
The square of a whole number n lies between 80 and 150, so n lies between √80 and √150.

\sqrt{80} \approx 8.9 \\
\sqrt{150} \approx 12.2

n is a whole number and lies between 8.9 and 12.2, so n can be 9, 10, 11, or 12.

The possible values for n are 9, 10, 11, and 12.
5 0
4 years ago
Assume that human body temperatures are normally distributed with a mean of 98.22 degrees Upper F 98.22°F and a standard deviati
Anna35 [415]

Answer: 0.00102%

Step-by-step explanation:

Given : Human body temperatures are normally distributed with a mean of \mu=98^{\circ}Fand a standard deviation of s=0.61^{\circ}F

A hospital uses 100.6^{\circ}F as the lowest temperature considered to be a fever.

Let x be the random variable that represents the human body temperatures.

z=\dfrac{x-\mu}{s}

For x= 100.6, z=\dfrac{100.6-98}{0.61}=4.26229508197\approx4.26

Using normal distribution table for z-values for right-tailed area ,

P(x>100.6)=P(Z>4.26)=0.0000102=0.00102\%

Hence, the required probability = 0.00102%

8 0
3 years ago
Can someone please help me with this!
Virty [35]
The answer for number 3 is 3.c
5 0
3 years ago
Read 2 more answers
I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th
stellarik [79]

Answer:

The number of once is 9.1  

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18             .........1

100 × H + 1 × O = 900          ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴   H = \frac{882}{99}

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e  O = 18 - 8.9

∴    O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1  and The number of hundreds is 8.9

Answer

4 0
4 years ago
URGENT PLEASE!!!!!!!!!!!!
kondaur [170]

Answer:

i got 178

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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